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Subjects>Math>Statistics

What is the difference between Dynaset and snapshot in VB?

Anonymous

∙ 13y ago

Updated: 9/28/2023

a dynaset object can be used to retrieve information from a recordset and use the resault of the query to then edit the records and it also can get resaults from more than one table. On the other hand the snaphot gets information from only one table on the query and the data can not be edited or updated

Wiki User

∙ 13y ago

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Q: What is the difference between Dynaset and snapshot in VB?

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Volume of a truncated rectangular based pyramid?

(1)Best formula to use is as follows -V = h/3(Areatop + √(Areatop*Areabottom) + Areabottom)(2)To find (h) using a tape measure -Areatop => bdAreabase => acLateral edge remaining => e (from top corner to base corner)k = 1 - √(bd/ac)H= √([e/k]² - [a/2]² - [c/2]²)h = HkV = H/3*(ac-bd+bd*k)(3)Lets say Top is a rectangle with sides b & dand bottom is a rectangle with sides a & c respectively.Let height be hin that case the volume of Truncated Pyramid with rectangular base will be -V = 1/3((a²c-b²d)/(a-b))hBUT BE CAREFUL - a,b,c,d are not all independent variables (one depends on the others) so this answer is misleading!!!Proof -Suppose the height of Full Pyramid is HFrom parallel line property(H-h)/H = b/aRearrangingH = ah/(a-b) --------------------(1)AlsoSince V=1/3 Base area X HeightVolume of full pyramid = 1/3 X ac X HVolume of removed Pyramid = 1/3 X bd X (H-h)So volume of truncated part V = 1/3(acH-bd(H-h))=1/3((ac-bd)H + bdh)From (1)V = 1/3((ac-bd)ah/(a-b) + bdh)reducing and rearranging we getV = 1/3((a²c-b²d)/(a-b))h(4)In case the truncated solid forms a prism instead, we have following formula -V = ( h/6)(ad + bc + 2ac + 2bd)Proof -Fig(1)Fig(2)Lets divide the fig(1) into four different shapes as shown in fig(2)VA = Volume of cuboid = bdhVB = Volume of prism after joining both Bs= ½ X base X height X width = ½ (a-b) (d)(h)VC = Volume of prism after joining both Cs = ½ X base X height X width = ½ (c-d) (b)(h)VD = Volume of rectangular pyramid after joining all Ds = 1/3 X base area X height =1/3 (a-b) (c-d) hThen V = VA + VB + VC + VDOr, V = bdh + 1/2(a-b)dh +1/2(c-d)bh + 1/3(a-b)(c-d)hArranging and simplifying we get -V = ( h/6)(ad + bc + 2ac + 2bd)

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