The mean of the 10th and 11th values
The mean of the 6th and 7th values
The mean of the 3rd and 4th values
The mean of the 19th and 20th values
The lower quartile is the second smallest and the upper quartile is the fourth smallest (second largest).
The range.
This difference is called the range. Subtract the smallest value (S) from the largest value (L).Formula: L - S = Difference
RangeThe term for the difference between the smallest and the largest values in a set of data is called the range. It is probably derived from the idea that the values of the numbers in the data could range anywhere from the lowest to the highest values but not beyond. The range is a measure of how disperse (spread out) the values are but it is not a very powerful measure.
The answer is 16. The range is the difference between the largest and smallest values: Largest: 7 Smallest: -9 Difference = 7 - (-9) = 16
The "range" is just the difference between the largest and smallest values. The largest number is 64 and the smallest number is 36. So, the range of this data is 64 - 36 = 28!
You find the the smallest and largest values. The interval is the largest minus the smallest.
The range is defined as the difference between the largest and the smallest values. One of these is known to be 0. If all the other numbers are negative, then the range is the absolute value of the smallest number whereas if all the other numbers are positive, the range is the largest number.
Yes. In the field of "ordered statistics" it makes no difference if data is ranked smallest to highest or vice-versa, but the convention is to consider rank = 1 the smallest value and rank = m the largest value of m values.
The range is just the difference between the largest and smallest values lowest (0) and highest (6) for a range of 6.
The smallest value is -32,768 and the maximum is 32,767
It is the largest value less the smallest one.
final double[] ns = new double[10]; final Random rnd = new Random(System.currentTimeMillis()); // Fill... for (int i = 0; i < ns.length; ++i) { ns[i] = rnd.nextDouble(); } // Get largest/smallest... double largest = Double.MIN_VALUE; double smallest = Double.MAX_VALUE; for (double n : ns) { if (n > largest) { largest = n; } if (n < smallest) { smallest = n; } } // largest and smallest are now the proper values.