K2Cr2O4 is not true, must be K2CrO4.
Differences are;
K2Cr2O7: Potasium dichromate is red-orange crystalline solid.
K2CrO4: Potasium chromate is yellow odorless powder.
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K2Cr2O7 is potassium dichromate, while K2Cr2O4 is potassium chromate. K2Cr2O7 is an orange-red compound used as an oxidizing agent, while K2Cr2O4 is a yellow compound. K2Cr2O7 tends to be more powerful as an oxidizing agent compared to K2Cr2O4.
The balanced equation between potassium dichromate (K2Cr2O7) and oxalic acid (H2C2O4) is: K2Cr2O7 + 3H2C2O4 -> Cr2(C2O4)3 + 2K2C2O4 + 4H2O
The symbolic equation for the reaction between potassium dichromate (K2Cr2O7) and barium chloride (BaCl2) is: K2Cr2O7 + 3BaCl2 -> 3BaCrO4 + 2KCl
To find the amount of potassium in K2Cr2O7, calculate the molar mass of K2Cr2O7 first. The molar mass of K2Cr2O7 is 294.2 g/mol. Potassium accounts for 239.1 g/mol = 78.2 g/mol in K2Cr2O7, so in 21.6 g of K2Cr2O7, there are 21.6 g * (239.1 g/mol / 294.2 g/mol) = 5.77 g of potassium.
To prepare a 0.1 N solution of K2Cr2O7 (potassium dichromate), you would need to dissolve 4.903 grams of K2Cr2O7 in enough water to make 1 liter of solution. Weigh out the exact amount of K2Cr2O7 using a balance, then dissolve it in water and make up the volume to 1 liter. This will give you a 0.1 N solution of K2Cr2O7.
The compound K2Cr2O7 is potassium dichromate. It is a bright orange solid commonly used in laboratories as an oxidizing agent and for various chemical reactions.