The balanced equation between potassium dichromate (K2Cr2O7) and oxalic acid (H2C2O4) is: K2Cr2O7 + 3H2C2O4 -> Cr2(C2O4)3 + 2K2C2O4 + 4H2O
The symbolic equation for the reaction between potassium dichromate (K2Cr2O7) and barium chloride (BaCl2) is: K2Cr2O7 + 3BaCl2 -> 3BaCrO4 + 2KCl
To find the amount of potassium in K2Cr2O7, calculate the molar mass of K2Cr2O7 first. The molar mass of K2Cr2O7 is 294.2 g/mol. Potassium accounts for 239.1 g/mol = 78.2 g/mol in K2Cr2O7, so in 21.6 g of K2Cr2O7, there are 21.6 g * (239.1 g/mol / 294.2 g/mol) = 5.77 g of potassium.
To prepare a 0.1 N solution of K2Cr2O7 (potassium dichromate), you would need to dissolve 4.903 grams of K2Cr2O7 in enough water to make 1 liter of solution. Weigh out the exact amount of K2Cr2O7 using a balance, then dissolve it in water and make up the volume to 1 liter. This will give you a 0.1 N solution of K2Cr2O7.
The compound K2Cr2O7 is potassium dichromate. It is a bright orange solid commonly used in laboratories as an oxidizing agent and for various chemical reactions.
The balanced equation between potassium dichromate (K2Cr2O7) and oxalic acid (H2C2O4) is: K2Cr2O7 + 3H2C2O4 -> Cr2(C2O4)3 + 2K2C2O4 + 4H2O
The symbolic equation for the reaction between potassium dichromate (K2Cr2O7) and barium chloride (BaCl2) is: K2Cr2O7 + 3BaCl2 -> 3BaCrO4 + 2KCl
To prepare a 0.25N K2Cr2O7 solution, you would dissolve 12.43 grams of K2Cr2O7 in enough water to make 1 liter of solution. This will give you a molarity of 0.25N for potassium dichromate (K2Cr2O7) in the solution.
The chemical formula for potassium dichromate is K2Cr2O7.
The chemical reaction between hydrogen peroxide (H2O2) and potassium dichromate (K2Cr2O7) in acidic medium produces chromium(III) sulfate (Cr2(SO4)3), water (H2O), and oxygen gas (O2). This reaction is used in the laboratory to test for the presence of alkenes due to the oxidizing properties of potassium dichromate.
To find the amount of potassium in K2Cr2O7, calculate the molar mass of K2Cr2O7 first. The molar mass of K2Cr2O7 is 294.2 g/mol. Potassium accounts for 239.1 g/mol = 78.2 g/mol in K2Cr2O7, so in 21.6 g of K2Cr2O7, there are 21.6 g * (239.1 g/mol / 294.2 g/mol) = 5.77 g of potassium.
To prepare a 0.1 N solution of K2Cr2O7 (potassium dichromate), you would need to dissolve 4.903 grams of K2Cr2O7 in enough water to make 1 liter of solution. Weigh out the exact amount of K2Cr2O7 using a balance, then dissolve it in water and make up the volume to 1 liter. This will give you a 0.1 N solution of K2Cr2O7.
Aldehydes is the product name of ovi dation of ethanol with k2Cr2O7.
The compound K2Cr2O7 is potassium dichromate. It is a bright orange solid commonly used in laboratories as an oxidizing agent and for various chemical reactions.
Potassium dichromate
The reaction between potassium dichromate (K2Cr2O7) and iron(II) sulfate (FeSO4) results in a double displacement reaction producing iron(III) chromate (Fe2(CrO4)3) and potassium sulfate (K2SO4). The balanced equation is: 3FeSO4 + K2Cr2O7 β Fe2(CrO4)3 + K2SO4.
K2Cr2O7(aq) ------> 2K+(aq)+Cr2O72-(aq)