K2Cr2O4 is not true, must be K2CrO4.
Differences are;
K2Cr2O7: Potasium dichromate is red-orange crystalline solid.
K2CrO4: Potasium chromate is yellow odorless powder.
potassium dichromate
K2Cr2O7(aq) ------> 2K+(aq)+Cr2O72-(aq)
potassium dichromate- K2Cr2O7 12.5 grams K2Cr2O7 *(1 mol K2Cr2O7/294 grams K2Cr2O7)= .0425 mols K2Cr2O7 There's two mols of K (potassium) for every 1 mol of K2Cr2O7 (Potassium Dichromate) so you multiply the K2Cr2O7 by two to get mols of K .0425 mols K2Cr2O7*(2 mols K/1 mol K2Cr2O7)=.085 mols K Multiply by the molar mass of K to get grams .85 mols K*(39 grams/1 mol K)= 3.32 grams potassium
Weigh 4.9035g K2Cr2O7 make up to 1 liter
No, It's totally different. 1M of K2Cr2O7 is 294.19g/water 1L on the other hands, 1N of K2Cr2O7 is 49.04 g/ water 1L
There is no reaction between H2O2 and K2Cr2O7 because both are oxidants.
potassium dichromate
K2Cr2O7(aq) ------> 2K+(aq)+Cr2O72-(aq)
1N of k2cr2o7=49.09 gm/1 L 0.25N=12.2725 gm of k2cr2o7 in 1 L of water.
The chemical formula of potassium dichromate is K2Cr2O7
potassium dichromate- K2Cr2O7 12.5 grams K2Cr2O7 *(1 mol K2Cr2O7/294 grams K2Cr2O7)= .0425 mols K2Cr2O7 There's two mols of K (potassium) for every 1 mol of K2Cr2O7 (Potassium Dichromate) so you multiply the K2Cr2O7 by two to get mols of K .0425 mols K2Cr2O7*(2 mols K/1 mol K2Cr2O7)=.085 mols K Multiply by the molar mass of K to get grams .85 mols K*(39 grams/1 mol K)= 3.32 grams potassium
Weigh 4.9035g K2Cr2O7 make up to 1 liter
No, It's totally different. 1M of K2Cr2O7 is 294.19g/water 1L on the other hands, 1N of K2Cr2O7 is 49.04 g/ water 1L
K2Cr2O7 + Na2C2O4 --> K2C2O4 + Na2Cr2O7
The titer volume of the sample gives the volume of Ferrous Ammonium Sulphate required to react with the excess potassium dichromate in the solution. Similarly, the titer volume for the blank (distilled water) gives the volume of Ferrous Ammonium Sulphate required to react with the excess potassium dichromate in the blank. The equation for the titration can be expressed as: Cr2O72 -- + FeSO4 (NH4)2SO4 = Cr+ + NH4+ + Fe 3+ From above equation it can be seen that one molecule of dichromate corresponds to one molecule of Mohr's salt. Thus, the difference in volume of excess K2Cr2O7 reacting with Mohr's solution can be calculated from the expression: = (Original vol. K2Cr2O7 -- vol. of K2Cr2O7 used for oxidation) solution - (Original vol. K2Cr2O7 -- vol. of K2Cr2O7 used for oxidation) blank = (Vol. of K2Cr2O7 used for oxidation) blank - Vol. of K2Cr2O7 used for oxidation) solution Hence, the difference in the titer volume for the solution and the blank is used to find out the Chemical Oxygen Demand directly.
Aldehydes is the product name of ovi dation of ethanol with k2Cr2O7.
K2Cr2O7+14HCl ---> 3Cl2 + 2CrCl3 + 2KCl + 7H2O