potassium superoxide
The chemical formula of potassium superoxide is KO2.
The balanced chemical equation for the reaction would be: 4KO2 + 2CO2 → 2K2CO3 + 3O2 Since the molar ratio between KO2 and O2 is 4:3, 0.400 mol of KO2 would produce: 0.400 mol KO2 * (3 mol O2 / 4 mol KO2) = 0.300 mol O2
KO2
323.2 grams of KO2 is equal to 4.55 moles of KO2. Per the equation, 3.4125 moles of O2 is produced which is equal to 2.055 E24 molecules of oxygen. This means that every mg of KO2 produces 6.36 E18 molecules of O2.
The reaction is:4KO2 + 2H2O ---> 4KOH + 3O2
The oxidation number for oxygen (O) in KO2 is -1. Since the overall charge of the compound is 0, the oxidation number of potassium (K) is +1.
You would need 18 grams to get the requirement. Using a chemical equation can help to solve this for you.
when k(potassium)added too(oxygen),it forms ko2(potassium oxide)because one molecule of k is reacted with o which contians always two molecules that means o+o=o2,therefore k+o=ko2 not k2o and there is one more reason that when one metal react with oxygen it forms oxides that is O2
This question can not be answered because KO2 is not an existing chemical compound and the probable mistaken compound K2O (potassium oxide) does not produce free oxygen (O2) in a normally possible chemical reaction.
K + o2 = ko2
The correct formula for peroxide is option (c) KO2. This compound contains the peroxide ion O2^2- and potassium cation K^+.
Use.PV = nRTTo get moles O2. ( 20.0o C = 293.15 Kelvin )(1.00 atm)(1120.0 L) = (X moles)(0.08206 L*atm/mol*K)(293.15 K)Moles = 1120.0/24.56= 45.60 moles O2-----------------------------------now,45.60 moles O2 (1 mole KO2/2 mole O2)(71.1 grams/1 mole KO2)= 1621 grams potassium oxide required=============================