J S N Y stands for Japan Society for the Promotion of Science, which is a funding agency in Japan that supports research and education in all fields of science.
To find the acceleration, first resolve the forces F1 and F2 into their x and y components. The x-component of F1 is 20 N and the x-component of F2 is 15 N * cos(60 deg). The y-component of F2 is 15 N * sin(60 deg). The net force in the x-direction is 20 N + 7.5 N, and the net force in the y-direction is 15 N * sin(60 deg). Then, calculate the net force by using the Pythagorean theorem on the x and y components. Finally, divide the net force by the mass of 8 kg to get the acceleration.
they are to be balmed becuase they make people who have high leveled cholestorol are more to die or to be dependent on a weelchair h a j e r a l r a y n i
Examples are: H, O, C, P, S, I, B, N, F, S, V, K, U, Y, W.
It is the jingle to remind the planets according to their distance from the sun in the solar system. Your is pronounced to me as my: M(Mercury)y V(Venus)ery E(Earth)ager M(Mars)other J(Jupiter)ust S(Saturn)erved U(Uranus)s N(Neptune)achos.
That is the correct spelling of sedimentary (rock formed from sediments).
E E-G--J---N----S-----Y E (F) G (HI) J (KLM) N (OPQR) S (TUVWX) Y Thats how i figured it out ^^^
E
E
d
E The number of letters between Y and S is one less than the number of letters between S and N, which is one less than N and J etc. YXWVUTS SRQPON NMLKJ JIHG GFE
S
pins
Eyou count backwards.Y to S = 6S to N = 5N to J = 4J to G = 3then G to E = 2
The solution is based on the distance between the letters in the alphabet, as the distance between Y and S is 6, between S and N is 5, between N and J is 4, and so forth. The next result after E would be D, and then the puzzle freezes.
The words that you can spell out of j t o n q y o u y are you, to and Tony
#include#includeint *bubble(int a[],int n);int *y;int j,i;void main(){int value[]={10,2,3,5,9,6,2,3,6,8};int n;clrscr();n=sizeof(value)/sizeof(int);y=bubble(value,n);for(i=0;i
#include<stdio.h> #include<conio.h> void main() { int a[10][10],i,j,k,m,n; printf("enter the order"); scanf("%d",&m,&n); for(i=0;i<m;i++) { for(j=0;j<n;j++) { scanf("%d",&a[i][j]); } } for(k=0;k<m;k++) { for(i=0;i<=m-1;i++) { for(j=0;j<n-i-1;j++) { if(a[k][j]>a[k][j+1]) temp=a[k][j]; a[k][j]=a[k][j+1]; a[k][j+1]=temp; } } } for(i=0;i<m;i++) { for(j=0;j<n;j++) { printf("sorted matrix=%d",a[i][j]); } } getch(); }