Jewish Singles in New York
Becuase atoms are so small that scientist have create models to describe them.
they are to be balmed becuase they make people who have high leveled cholestorol are more to die or to be dependent on a weelchair h a j e r a l r a y n i
It is the jingle to remind the planets according to their distance from the sun in the solar system. Your is pronounced to me as my: M(Mercury)y V(Venus)ery E(Earth)ager M(Mars)other J(Jupiter)ust S(Saturn)erved U(Uranus)s N(Neptune)achos.
Examples are: H, O, C, P, S, I, B, N, F, S, V, K, U, Y, W.
Mars, closer to the sun after the Asteroid Belt, and Saturn further from the sun. , My Very Educated Mother Just Served Us Nachos e ,,e ,,,,,a ,,,,,,,,,,,,,a ,,,,,,,,,u ,,,,,a ,,,,,,,,,r ,,e r ,,,n ,,,,,r ,,,,,,,,,,,,,,r ,,,,,,,,,p ,,,,,t ,,,,,,,,,a ,,p c ,,,u ,,,,,t ,,,,,,,,,,,,,s ,,,,,,,,,,i ,,,,,u ,,,,,,,,,n ,,t u ,,,s ,,,,,h ,,,,,,,,,,,,,,,,,,,,,,,,t ,,,,,,r ,,,,,,,,,u ,,u r ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,e ,,,,,n ,,,,,,,,,s ,,n y ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,r ,,,,,,,,,,,,,,,,,,,,,,e
E E-G--J---N----S-----Y E (F) G (HI) J (KLM) N (OPQR) S (TUVWX) Y Thats how i figured it out ^^^
E
E
d
E The number of letters between Y and S is one less than the number of letters between S and N, which is one less than N and J etc. YXWVUTS SRQPON NMLKJ JIHG GFE
S
pins
Eyou count backwards.Y to S = 6S to N = 5N to J = 4J to G = 3then G to E = 2
The solution is based on the distance between the letters in the alphabet, as the distance between Y and S is 6, between S and N is 5, between N and J is 4, and so forth. The next result after E would be D, and then the puzzle freezes.
The words that you can spell out of j t o n q y o u y are you, to and Tony
#include#includeint *bubble(int a[],int n);int *y;int j,i;void main(){int value[]={10,2,3,5,9,6,2,3,6,8};int n;clrscr();n=sizeof(value)/sizeof(int);y=bubble(value,n);for(i=0;i
#include<stdio.h> #include<conio.h> void main() { int a[10][10],i,j,k,m,n; printf("enter the order"); scanf("%d",&m,&n); for(i=0;i<m;i++) { for(j=0;j<n;j++) { scanf("%d",&a[i][j]); } } for(k=0;k<m;k++) { for(i=0;i<=m-1;i++) { for(j=0;j<n-i-1;j++) { if(a[k][j]>a[k][j+1]) temp=a[k][j]; a[k][j]=a[k][j+1]; a[k][j+1]=temp; } } } for(i=0;i<m;i++) { for(j=0;j<n;j++) { printf("sorted matrix=%d",a[i][j]); } } getch(); }