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.5 moles of tin because the half reaction for tin is Sn+4 + 2e- -> Sn+2 since there are 2 electrons needed, for one mole of Sn, 1 faraday would only produce a half of a mole of Sn.
The reaction between HCl (hydrochloric acid) and Sn (tin) forms SnCl2 (tin(II) chloride) and hydrogen gas (H2). The balanced chemical equation for this reaction is: Sn + 2HCl → SnCl2 + H2.
The balanced chemical equation shows a 1:1 ratio between Sn and SnF2. Since Sn is limiting in this reaction, the maximum amount of SnF2 that can be produced will be equal to the amount of Sn used, which is 0.480 moles. Therefore, 0.480 moles of SnF2 can be produced.
The oxidation number of Sn changes from +4 in SnCl4 to +2 in SnCl2, resulting in a decrease of 2.
The balanced chemical equation for the reaction of Sn with HCl to produce H2 gas is: Sn + 2HCl → SnCl2 + H2. According to the equation, 1 mole of Sn produces 1 mole of H2 gas, thus if 6.75 moles of Sn is consumed, then 6.75 moles of H2 gas will be produced.
The SN reaction is a substitution reaction. An example of the SN reaction is Br. H3CH2C.
.5 moles of tin because the half reaction for tin is Sn+4 + 2e- -> Sn+2 since there are 2 electrons needed, for one mole of Sn, 1 faraday would only produce a half of a mole of Sn.
6
The reaction between HCl (hydrochloric acid) and Sn (tin) forms SnCl2 (tin(II) chloride) and hydrogen gas (H2). The balanced chemical equation for this reaction is: Sn + 2HCl → SnCl2 + H2.
fusion
The product of Sn with HCl is tin chloride (SnCl2) and hydrogen gas (H2). The reaction can be represented as Sn + 2HCl -> SnCl2 + H2.
No because zinc is more reactive than tin so it dilutes it
The balanced chemical equation shows a 1:1 ratio between Sn and SnF2. Since Sn is limiting in this reaction, the maximum amount of SnF2 that can be produced will be equal to the amount of Sn used, which is 0.480 moles. Therefore, 0.480 moles of SnF2 can be produced.
To find the grams of Sn formed, we first need to calculate the number of moles of SnO2 in 12.5 grams. Then, we use the stoichiometry of the reaction to relate the number of moles of SnO2 to the number of moles of Sn. Finally, we convert the moles of Sn to grams using the molar mass of Sn.
The oxidation number of Sn changes from +4 in SnCl4 to +2 in SnCl2, resulting in a decrease of 2.
The balanced chemical equation for the reaction of Sn with HCl to produce H2 gas is: Sn + 2HCl → SnCl2 + H2. According to the equation, 1 mole of Sn produces 1 mole of H2 gas, thus if 6.75 moles of Sn is consumed, then 6.75 moles of H2 gas will be produced.
Sn4+ is fully oxidised, Sn2+ only half