Wiki User
ā 11y agoFor aerodynamic objects falling short distances, there will not be much air resistance. The only force involved will be gravity and therefore we would need to assume the terminal speed of the falling object. If a Baseball, for example, the terminal speed would be 131 feet per second so that a distance of 324 feet the ball would take 2.47 seconds. If the ball is Golf ball, the terminal speed would be 98.4 feet per second making the drop time 3.29 seconds. As a matter of interest, a vertical skydiver would take 1.16 seconds to cover the same distance.
Wiki User
ā 11y agoa. 144 feet b. 96 ft/sec.
A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the velocity of the ball the instant before it hits the ground?
There is no scientific evidence to suggest that ball lightning can destroy a building. Ball lightning is a rare and poorly understood phenomenon that typically lasts only a few seconds and dissipates harmlessly. Its effects on structures are largely unknown.
381 metres
Yes, the ball will hit the ground in approximately 4.52 seconds. This calculation is based on the formula: ( t = \sqrt{\frac{2h} {g}} ), where h is the height of the building (80m) and g is the acceleration due to gravity (9.8 m/sĀ²).
The golf ball.
5 seconds
The height of the building can be calculated using the formula: h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (9.8 m/s^2), and t is the time taken to reach the ground (1.0 seconds in this case). Substituting the values, we get h = (1/2)(9.8)(1.0)^2 = 4.9 meters. Therefore, the height of the building is 4.9 meters.
It could if you slammed the bouncy ball on the ground hard enough, or if you dropped it from a 30 story building. probably not
The ball would take approximately 4 seconds to hit the ground, neglecting air resistance. This calculation is based on the constant acceleration due to gravity (9.8 m/sĀ²), assuming the ball is dropped and not thrown.
To calculate the velocity of the ball, we need to know the height from which it was dropped. If the ball was dropped from rest, we can use the formula for free fall motion: velocity = (acceleration due to gravity * time). Assuming the acceleration due to gravity is 9.81 m/s^2, the velocity of the ball hitting the ground after 3.03 seconds would be around 29.7 m/s.
You put in on the ground on top of a hill and let go. What kind of sense does that question make?