For aerodynamic objects falling short distances, there will not be much air resistance. The only force involved will be gravity and therefore we would need to assume the terminal speed of the falling object. If a Baseball, for example, the terminal speed would be 131 feet per second so that a distance of 324 feet the ball would take 2.47 seconds. If the ball is Golf ball, the terminal speed would be 98.4 feet per second making the drop time 3.29 seconds. As a matter of interest, a vertical skydiver would take 1.16 seconds to cover the same distance.
a. 144 feet b. 96 ft/sec.
There is no scientific evidence to suggest that ball lightning can destroy a building. Ball lightning is a rare and poorly understood phenomenon that typically lasts only a few seconds and dissipates harmlessly. Its effects on structures are largely unknown.
381 metres
To calculate the velocity of the ball just before it hits the ground, we can use the equation of motion: velocity = acceleration x time. The acceleration due to gravity is approximately 9.8 m/s^2. Given the time of 3.0 seconds, we can plug these values into the equation to find the velocity. Therefore, the velocity of the ball just before it hits the ground is 29.4 m/s.
5 seconds
The golf ball.
Yes, the ball will hit the ground in approximately 4.52 seconds. This calculation is based on the formula: ( t = \sqrt{\frac{2h} {g}} ), where h is the height of the building (80m) and g is the acceleration due to gravity (9.8 m/s²).
The height of the building can be calculated using the formula: h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (9.8 m/s^2), and t is the time taken to reach the ground (1.0 seconds in this case). Substituting the values, we get h = (1/2)(9.8)(1.0)^2 = 4.9 meters. Therefore, the height of the building is 4.9 meters.
It could if you slammed the bouncy ball on the ground hard enough, or if you dropped it from a 30 story building. probably not
The ball would take approximately 4 seconds to hit the ground, neglecting air resistance. This calculation is based on the constant acceleration due to gravity (9.8 m/s²), assuming the ball is dropped and not thrown.
If it was thrown horizontally or dropped, and hit the ground 3.03 seconds later, then it hit the ground moving at a speed of 29.694 meters (97.42-ft) per second. If it was tossed at any angle not horizontal, and hit the ground 3.03 seconds later, we need to know the direction it was launched, in order to calculate the speed with which it hit the ground.
You put in on the ground on top of a hill and let go. What kind of sense does that question make?