2CH3OH(l)+3O2(g)→2CO2(g)+4H2O(l)ΔH=−726kJ
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To calculate the energy released when methanol reacts, you need the heat of combustion of methanol. The heat of combustion of methanol is around -726.1 kJ/mol. Calculate the number of moles of methanol in 81.4 g, then multiply by the heat of combustion to find the energy released.
The standard enthalpy of combustion for methanol is about -726 kJ/mol. To calculate the energy released when 40.0 g of methanol is burned, first convert the mass to moles using the molar mass of methanol (32.04 g/mol). Then, multiply the moles by the enthalpy of combustion to find the total energy released.
there is no "symbol" as such for methanol as it is not an element, it is a compound and a compound is made up of two or more elements. the formula of the compound methanol is CH3OH sometimes this is abreviated to MeOH
Methanol (CH3OH) has 14 electrons. There are 1 electron in carbon, 1 in each hydrogen, 4 in oxygen, and 8 in a lone pair on oxygen.
Methanol has one non-bonding electron. This electron is located on the oxygen atom, as oxygen typically has two lone pairs of electrons in its valence shell.
One carbon atom attached with three hydrogen atoms and OH (alcohol) functional group