Atlantic herring (raw): - 100 g has 158 kcal - 1 fillet (184 g) has 291 kcal Pacific herring (raw): - 100 g has 195 kcal - 1 fillet (184 g) has 359 kcal.
1 kcal = 1000 cal. 1 cal = 4.18 J
The difference between kcal and cal is 1000 cal = 1 kcal. However, we usually count food calories with kcal, and use kcal and cal interchangeably. Therefore, 9 kcal [Food Calories] = 9 cal. So, to the point: If there are 9 kcal in 1 g of fat, there are 9000 kcal in 1 kg of fat (1 kg = 1000 g).
Fat = 9 kcal 2,200 kcal x 0.30 kcal = 660 kcal 660 / 9 kcal = 73.33 g = 73 g of fat per day
9 kcal/g
Approx. 86 kcal/100 g.
The specific heat capacity of aluminum is 0.897 J/g°C. To convert this to kcal/g°C, we divide by 4.184 to get 0.214 kcal/g°C. Therefore, the total kilocalories of heat required to raise the temperature of 225g of aluminum from 20°C would be 225g * 20°C * 0.214 kcal/g°C = 966 kcal.
Simply - your recommended daily caloric intake consists of three types of so called macronutrients: Carbohydrates, found in bread, rice, paste, ... - at 4 kcal/g Protein, found in fish, beef, poultry, eggs - at 4 kcal/g Fats, found in Oil, Meat, butter - at 9 kcal/g so if your recommended intake ist 2000 kcal/day and 50g of fats you could eat like this: 50 g fats * 9 = 450 kcal 150 g protein * 4 = 600 kcal 250 g carbs *4 = 1000 kcal ------------------------------------ approx. 2000kcal of course if you eat less protein and more fat (typical western diet) you could have this: 100 g fats * 9 = 900 kcal 50 g protein * 4 = 200 kcal 200 g carbs *4 = 800 kcal ------------------------------------ approx. 1900kcal So you BELOW recommend kcal but ABOVE recommend fat intake. Hope this helps.
100 g of dried spaghetti has about 384 kcal which is 1456 kilojoules.
The energy content of water at 373 K can be calculated using the specific heat capacity of water, which is 4.18 J/g°C. At 373 K, the specific heat capacity would be approximately 1.00 kcal/kg°C. Therefore, the energy content of 1 kg of water at 373 K would be approximately 373 kcal.
· 1 J/(kg K) = 2.389x10-4 kcal/(kg oC) = 2.389x10-4 Btu/(lbm oF) · 1 kJ/(kg K) = 0.2389 kcal/(kg oC) = 0.2389 Btu/(lbm oF) · 1 Btu/(lbm oF) = 4,186.8 J/ (kg K) = 1 kcal/(kg oC) · 1 kcal/(kg oC) = 4,186.8 J/ (kg K) = 1 Btu/(lbm oF) Metal Specific Heat Capacity - cp (kJ/kg K)(kcal/kgoC) (Btu/lbmoF) Lead 0.13 0.031 0.03 · 1 J/(kg K) = 2.389x10-4 kcal/(kg oC) = 2.389x10-4 Btu/(lbm oF) · 1 kJ/(kg K) = 0.2389 kcal/(kg oC) = 0.2389 Btu/(lbm oF) · 1 Btu/(lbm oF) = 4,186.8 J/ (kg K) = 1 kcal/(kg oC) · 1 kcal/(kg oC) = 4,186.8 J/ (kg K) = 1 Btu/(lbm oF) Metal Specific Heat Capacity - cp (kJ/kg K)(kcal/kgoC) (Btu/lbmoF) Lead 0.13 0.031 0.03
Assuming 4 kcal/g for carb and protein and 9 kcal/g for fats, the total would be (15 x 9) + (25 x 4) + (20 x 4) = 315 kcal.