Ha. I think you mean kilojoules, which would be 1000.
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In a group of 100 people 27 like cold drink and 37 like hot drinks how many people like both drink
190
1 cal= 4.18 J
1 joule is 0,239 calories. so 515 x 0,239 = 123,085 calories
Q (heat) = mass*Specific Heat*Temperature differenceI assume 2.5 * 101 Joules? or 25 J & 10 grams of substance?25 J = 10 grams * (SH) * (70-10oC)25 J =10 g *60oC * SHSH = 25 J/(10 g * 60oC)S.H. = 0.0417 J/gOC
To determine how many degrees J will raise the temperature of g of water, we need to use the specific heat capacity formula: ( Q = mc\Delta T ), where ( Q ) is the heat added (in joules), ( m ) is the mass of the water (in grams), ( c ) is the specific heat capacity of water (approximately 4.18 J/g°C), and ( \Delta T ) is the change in temperature (in °C). Rearranging the formula gives ( \Delta T = \frac{Q}{mc} ). Without specific values for Q and g, we cannot calculate the exact change in temperature.