A pool 120 yds long by 54 yds wide and 8 ft deep has a volume of 120 x 3 ft x 54 x 3 ft x 8 ft = 466,560 ft3. 1 cubic foot of water has a volume of 7.4805 US gallons, so the volume of the pool would be about 3,490,100 US gallons (466,560 x 7.4805).
Perform the following multiplication. 120x72x22 and then divide the answer by 231. The final figure will be the amount in US Gallons.
1795 gallons, if you fill it to the brim.
Approx 17939 gallons.
598 Imperial gallons, approx.
18,691.2 gallons if shallow end 4'
It depends on how long the tank is. You only provided two dimensions. You need three. Please restate the question.
The average depth of the pool would be 5.5 feet, which is (8 + 3)/2 The volume of the pool would be 24 x 15 x 5.5 feet = 1980 cubic feet 1 cubic feet is 7.48051948 gallons The answer would be 14811.4286 gallons.
it only depends on pressure at which the water flows into the gallon
1346 gallons
1 ft.3 (cubic) of water = 7.48 gallons How high is the pool? Is it 24 foot wide, 54 foot long and how deep? diameter x diameter x average depth x 5.9 = total gallons Allowing for the overflow/filter access, fill to 48" deep and use 13,000 gallons in a flat-bottomed pool.
615,142 gallons of water are needed to fill this cylinder.
It will take 5,104.1 gallons of water to fill this cylinder.
Multiply all three dimensions to get the volume in cubic feet. Then multiply that product by 7.48 to convert to gallons.