Wiki User
∙ 14y agoPrevious answers http://wiki.answers.com/Q/How_much_water_will_an_18_foot_pool_by_4_feet_deep_hold
Wiki User
∙ 14y agoWiki User
∙ 12y agoYou are short one dimension. You need three dimensions to get volume, and you only gave two dimensions.
If that is 4 feet tall and 18 inches in diameter, it would be 16.83 gallons.
If this is a round pool that is 27 feet across by 52 inches tall and you fill it with 4 feet (48 inches) of water, the total volume would be 17,204 gallons of water.
A 16'x32'x52" pool holds up to 16,584gallons of water.
The pool would contain 160.43 cubic feet of water. But I'm sorry, I only speak metric so I don't know what that is in gallons.
Depends on the depth. If it is 4 feet deep and it is cicular with a diameter of 24 feet then you have approx. 13,553 gallons of water. If it is 3 feet deep then you have approx. 10,152 gallons of water.
One gallon of water is equal to approximately 231 cubic inches. Therefore, 400 gallons of water would measure approximately 92,400 cubic inches. To find the height in inches, divide the total cubic inches by the surface area of the container the water is in.
You would use the following formula: 30 (dia.ft) X 30 (dia.ft.) X 4.66 (avg.depth.ft.) X 5.9 (multiplication factor) = 24,744.6 gallons of water
One inch of rainfall on one acre is equivalent to 27,154 gallons of water. Therefore, four inches of rain on an acre would be equal to 108,616 gallons of water.
There would be approximately 12.7 gallons of water in the drum with 8 inches of water. This calculation is based on the formula for calculating the volume of a cylinder (V = πr^2h) where the radius is half of the diameter and the height is the depth of the water.
A 100-foot round pool filled with 1.5 feet of water would be holding about 88,500 gallons.
If it's round and 11 inches across on the inside, thenit can hold 579.2 ounces / 4.5 gallons full to the rim.
This container could hold up to 3,949.71 US gallons of water.