There is a simple formula for calculating volume of liquid in terms of imperial gallons as follows : [length (in inches)x width (in inches) x height(in inches)] divided by 231, so 1in. on 3200 sq.feet = the sum of 1 x 460800 divided by 231=1994.805 imperial gallons.As 1 imperial gallon=1.2005 US gallon, the volume of water therefore equals to 2394.76 US gallons.
3200 meters = 10,498.69 feet.
Easy its 64 gallons all you have to do is multiply length by width by height which in this case is 4x4x4=64. hope this helpsThe container's volume is 64 cubic feet (not 64 gallons).64 cubic feet = 64 x 1728 = 110,592 cubic inchesThe U.S. gallon = 231 cubic inches110,592 / 231 = 478.75 U.S. gallons in a 4 ft x 4 ft x 4 ft container.For Imperial gallons divide by 277.42 instead of 231.
188 gallons = 25.132 cubic feet (rounded)
about 5 gallons
Is 42 in inches or feet? I've answered the problem below for inches since that makes more sense for a pool. Volume of pool = area of pool * depth V = pi*r^2 * depth = 3.14*7.5*7.5*3.5 = 618 cubic feet The volume of 1 gallon of water = 0.133680556 cubic feet. Therefore, the # of gallons of water in the pool = 618/0.133680556 = 4623 gallons of water In actually, because of significant digits in the depth and diameter of pool, the answer would be approximately 4600 gallons of water
This unit conversion alone is impossible. This is because kilograms is a unit of measurement of weights. Whereas gallons is a unit of measurement of a liquid. If you said 3200 gallons of water then I can find the density of it in kilograms.
How many imperial gallons is 30 cubic feet of water?
3200 meters = 10,498.69 feet.
1,987 cubic feet = 14,860 gallons of water.
There are 8,483 gallons in 1,134 cubic feet of water.
4,088 cubic feet = 30,580 gallons of water.
31 cubic feet of water equates to ~231.9 gallons.
44,260 gallons of water.
58,168.52 gallons.
Four cubic feet is 29.92 gallons.
Six acre-feet of water is about 1,955,109 US gallons.
There are 7,985.76 gallons of water in a 1799.5 cubic feet pool.