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Improvement, or should I say correction, of this answer--

The correct answer is 53 Saturdays in 2011.

Please use common sense when answering these questions!! It is not possible for ANY day of the week to have only 51 occurrences in any year--because there are 52 weeks in every year. So any day of the week will have at least 52 occurrences in every year.

Now, why is it AT LEAST 52 occurrences? Because 52 weeks per year times 7 days per week equals only 364 days--and we all know that there are actually 365 days in a year (except leap years, where there are 366). So that means that in a non-leap year, the day of the week that falls on January 1 MUST also be the last day of the year as well (December 31). Which is why there are 53 Saturdays in 2011--it is both the first and last day of the year.

Now in a leap year, since there are two extra days than an even 52 weeks, that means that two days of the week will have 53 occurrences in that year--whatever days of the week fall on January 1 and January 2, will also fall on the last two days of the year, respectively.

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Q: How many Saturdays in 2011?
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