The work done by the system can be calculated using the formula: Work = Force × Distance × cos(θ). Since work is given as -2.37 kJ, we convert this value to joules (1 kJ = 1000 J). So, the work done is -2.37 kJ × 1000 J/kJ = -2370 J. Therefore, the work done by the system when it absorbs 650 J of energy during a change is -2370 J + 650 J = -1720 J or -1.72 kJ.
The energy content of one mole of glucose is approximately 2,810 kilojoules (kJ) or 2,810,000 joules (J).
One gram of protein contains about 4 kilojoules (kJ) of energy.
There are 9 kilojoules (kJ) in 1 gram of fat.
There are approximately 17 kilojoules (kJ) in 1 gram of protein.
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The work done by the system can be calculated using the formula: Work = Force × Distance × cos(θ). Since work is given as -2.37 kJ, we convert this value to joules (1 kJ = 1000 J). So, the work done is -2.37 kJ × 1000 J/kJ = -2370 J. Therefore, the work done by the system when it absorbs 650 J of energy during a change is -2370 J + 650 J = -1720 J or -1.72 kJ.
The energy E in joules (J) is equal to 1 kilojoule times 1000: E (J) = 1kJ × 1000 = 1000J . So 1 kilojoule (kJ) is equal to 1000 joules (J): 1 kJ = 1000 J .
Using the specific heat of water as 4180 J/kg/deg, and q = mC∆T one can calculate the heat needed.q = (0.4 kg)(4180 J/kg/deg)(5 deg) = 8360 J = 8.4 kJ (or 8 kJ to one significant figure)
specific heat of ice = 2.09 J/g/degree2.09 J/g/deg x 800 g x 5 deg = 8360 J = 8.4 kJ∆Hfusion = 334 J/g0.8kg x 334 J/g x 1000 g/kg x 1 kJ/1000 J = 267 kJ8.4 kJ + 267 kJ = 275.4 kJ
kJ for kilojoules and J for joules.
3.84 KJ
Approximately 2080 calories. one calorie = 4.184 KJ of energy
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12 J/3 moles = 4 J/mole. Thus, H of reaction in kJ/mole = 0.004 kJ/mole
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One gram of protein contains about 4 kilojoules (kJ) of energy.