You mean the formula v = u + at, where v is final velocity, u is starting velocity, a is the rate of acceleration and t is the time taken.
Well if a car's acceleration is 20 feet per second per second, in 12 seconds its velocity will have been increased to 20 x 12 = 240 feet per second.
So if before it accelerated it was travelling at 100 feet per second, its new speed will be 240 + 100 = 340 feet per second = 340 x 60 x 60 ft per hour = 1224000 ft/hr
which is just under 219 mph! Some car!
-1
In roman numerals, XII equals 12, and V equals 5. So as 12 plus 5 equals 17, XII plus V equals 17:) hope it helpedImproved Answer:XII+V = XVII (12+5 = 17)
v = -1
V plus VI Equals XI OR V Plus IV Equals IX
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v
-1
If: v = u+at Then: -u = -v+at or u = v-at (by dividing all terms by -1) a = (v-u)/t t = (v-u)/a
You use inverse operations !!
1 equation: as u know that a=(v-u)/t so, v-u=a*t therefore, v=u+at which is the first equation of motion
v equals five
In roman numerals, XII equals 12, and V equals 5. So as 12 plus 5 equals 17, XII plus V equals 17:) hope it helpedImproved Answer:XII+V = XVII (12+5 = 17)
v = -1
V plus VI Equals XI OR V Plus IV Equals IX
Rearranging: v² = u² + 2as → u² + 2as = v² ________________ writing equation the other way round to get u² on the left → u² = v² - 2as _________________ subtracting 2as from both sides → u = ±√(v² - 2as) ______________ taking the square root of both sides
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I'm assuming you mean the symbol (u) and not 'you'So:u = vw + zWhere vw means v * w (v times w)