It is the round with which the revolver was "proof fired" at the factory to test its functionality.
When it loses its head.
Usually a revolver, although a few rifles were made in that caliber.
The presently manufactured Taurus "Judge" in its many variations fits that bill in .410.
A buckshot is a large size shell that is carefully packed into shotguns. They are mainly used for hunting large game such as deer and moose. A buckshot can easily be fired without a shotgun if there was an explosion.
None. Some handguns have been made that will fire .45 Long Colt revolver rounds and .410 shotgun shells, but that does not mean that you can take any .410 shotgun and stick .45 handgun ammo in there.
When a shotgun is fired, the trigger is pulled, causing the firing pin to strike the primer on the shotgun shell. This ignites the gunpowder in the shell, creating a rapid expansion of gases that propel the shot or slug out of the barrel. The blast of the gases also causes the action to cycle, ejecting the spent shell casing and chambering a new shell if the shotgun is semi-automatic or pump-action.
American Heavy Machine Guns in WW2 fired .30 caliber rounds. The .50 caliber machine gun was 0.50 caliber which is 1/2-inch diameter and about 2 inches long. The shell before firing is about 6 inches in length.
The same as is it was fired from a gun, except the explosion would be broader.
Absolutely not. A .45 Long Colt bullet is nominally .455 inches in diameter. A .410 is .41 caliber. The cartridge will fit because of the extra chamber diameter to accommodate the thick body of the shotgun shell, but attempting to fire a revolver cartridge will result in overpressure, a burst barrel, and likely injury.The chamber pressure of a .45 LC is higher than a shotgun is designed to tolerate, to begin with.
No. The Luger was a 9mm gun and the 50 Desert Eage is a 50 caliber gun. The 9mm round would fall out of the barrel, and if you did manager to get it to fire, you could damage the gun and/or hurt yourself.
Written as .16 caliber (notice the decimal point?), that would be a VERY tiny bullet- .16 inches in diameter. That is smaller than a metal BB- which is between .17 and .18 inches. Written as 16 caliber (no decimal point) it would refer to the length of a cannon barrel- 16 times longer than it is wide. But you may have caliber confused with gauge- shotgun shell sizes are usually given in gauges. A 16 GAUGE shotgun is about .69 caliber- or .69 inches across the shell. They are smaller than a 12 gauge, bigger than a 20 gauge (with gauge, smaller number means bigger)