4s2 - 9 can be expressed by using the identity: a2 - b2 = (a-b)(a+b) Therefore, 4s2 - 9 = (2s)2 - 32 = (2s-3)(2s+3)
A = (s, 2s), B = (3s, 8s) The midpoint of AB is C = [(s + 3s)/2, (2s + 8s)/2] = [4s/2, 10s/2] = (2s, 5s) Gradient of AB = (8s - 2s)/(3s - s) = 6s/2s = 3 Gradient of perpendicular to AB = -1/(slope AB) = -1/3 Now, line through C = (2s, 5s) with gradient -1/3 is y - 5s = -1/3*(x - 2s) = 1/3*(2s - x) or 3y - 15s = 2s - x or x + 3y = 17s
2s(-s^3 + 2s^2 - 5) -2s(s^3 - 2s^2 + 5)
5-2=3 3+1=4 4x6=24
(2+2+2)=6 divided by the 4th 2 = 3
-6r 2s 5t 2
(1 x 3 ) x ( 2 X 4) = 24
It is found as follows:- Points: (s, 2s) and (3s, 8s) Slope: (2s-8s)/(s-3s) = -6s/-2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) Multiply all terms by 3: 3y-15s = -1(x-2s) => 3y = -x+17s In its general form: x+3y-17s = 0
The least common multiple (LCM) of 2, 8, and 12 is 24. To find the LCM, prime factorize each number. 2=2 8=2*2*2 12=2*2*3 Multiply each factor the greatest number of times it occurs in any of the numbers. 8 has the most twos, so take three 2s. 12 has one 3. 2*2*2*3=24 So 24 is the lowest common multiple of 2, 8, and 12.
Points: (s, 2s) and (3s, 8s) Slope: (8s-2s)/(3s-s) = 6s/2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) => 3y-15s = -1(x-2s) => 3y = -x+17x Perpendicular bisector equation in its general form: x+3y-17s = 0
5 / 5 = 1 2 + 1 = 3 8 x 3 = 24
3 x (22)2 + 2 = 50