No way to tell. You have only liste a partial serial number.
100-1000 or more depending on specifics
Browning Auto-5 'Light Twenty' made in 1967. Value from $450-$1000.
Fn never produced a Browning a5 with A "ZZ" . Are you sure it isn't "7Z?" a serial # of 7Z15649 would represent a Lightweight twenty made in 1967 auto5man
I can not find a number that matches that on the Browning website. The closest seems to be the Fabrique Nationale manufactured guns in 1953; however, those serial numbers only go up to 438000 and there is no "1-" at the beginning that I can tell. If it is any consolation, my own Browning 20 gauge serial number does not appear in the list either (7Z 21385). It may be worth while to call 800-333-3288, the Browning customer service line. I plan on it. The serial number website for Auto 5 shotguns is:http://www.browning.com/customerservice/dategun/detail.asp?id=13
7z+9 = 72 7z = 72-9 7z = 63 z = 9
7z + 6s + s = 7z + 7s This can then be factorised using 7 as the factor: 7z + 7s = 7(z + s)
7z - 9.4 = 11.6 7z = 11.6 + 9.4 = 21 z = 21/7 = 3
To express "7 times z reduced by a third of the product," we first calculate the product, which is (7z). A third of this product is (\frac{1}{3} \times 7z = \frac{7z}{3}). Therefore, reducing (7z) by this amount results in the expression (7z - \frac{7z}{3}). Simplifying this yields (\frac{21z}{3} - \frac{7z}{3} = \frac{14z}{3}).
x = Y + 7z
7+7z 7=7*1 7z=7*z 7(1+z) is factored form
2z+9.75-7z=-5.15
z / (1/7) = 7z.