what percentage of a mike carton comes from paper A. 85% B. 40% C. 20% D. 92%
40 C is higher.
Chemical Rubber Company
104 ℉
104°F = 40°C(104°F - 32) multiplied by 5/9 = 40°C
b/c they r!!!!!! b/c they r!!!!!! b/c they r!!!!!!
One half?
like this: R=redstone dust B=bow C=cobblestone C C C C B C C R C
b = 40 - a, c = 42 - a so b + c = 40 - a + 42 - a, ie 82 -2a = 34 so a = 48/2 ie 24 b = 40 - 24 ie 16 and c = 42 - 24 ie 18
a = variable b = 40%a a - b = c
Assume that B is 100% A therefore is 140% —> B + 40% C therefore is 120% —> B + 20% Therefore A : C = 140 : 120 Therefore A exceeds C by 16.67%
C. R. B. Joyce has written: 'Psychopharmacology: dimensions and perspectives'
First, let's define an equivalence relation. An equivalence relation R is a collection of elements with a binary relation that satisfies this property:Reflexivity: ∀a ∈ R, a ~ aSymmetry: ∀a, b ∈ R, if a ~ b, then b ~ aTransitivity: ∀a, b, c ∈ R, if a ~ b and b ~ c, then a ~ c.
R. C. B. Cooper has written: 'Preserving abstraction in concurrent programming'
The real notes for jingle bell rock on the alto sax are: 1.) gg g, gg g, gbga Bb a g r, r--, 1 measure rest 5.) bb b g- bb b g#- g- f#- g- f#- g- f#- r cccc c c f f- 13.) bb b bb b bb b g- bb b g# g- f#- g- f#- g- f#- r c#c# c(n) c b--- gg 21.) a- g eg a- a Bb b(n) b b b g--- gg a- g eg a- g- f# r gggg a a a- 29.) bb b bb b bb b g- bb b gg #g g a b c e eeee cc Eb Eb- r c# c(n) c 36.) r c# c(n) c r c#- c# c(n) c c- b---- > r g b > key n= natural -= half note ---= dotted hald note ----= whole note r= rest btw, the part at 21 is a saxophone solo!
#include<stdio.h> #include<conio.h> void main() { int a[3][3],b[3][3],c[3][3],r,c; for(r=0;r<=3;r++) { for(c=0;c<3;c++) { printf("\n enter the value="); scanf("%d%d",&a[r][c],&b[r][c]); } } printf("\n first matrix=\n"); for(r=0;r<=3;r++) { for(c=0;c<3;c++) { printf("%d\t",a[r][c]); } printf("\n"); } printf("\n scond matrix=\n"); for(r=0;r<=3;r++) { for(c=0;c<3;c++) {printf("%d\t",b[r][c]); } printf("\n"); } printf("\n sum of given matrix=\n"); for(r=0;r<=3;r++) { for(c=0;c<3;c++) { c[r][c]=a[r][c]+b[r][c]; printf("%d\t",c[r][c]); } printf("\n"); } getch(); }
ab[C]defghijklmnopqrstuvwxyz. Exuse me but i think it is [R]. It is [C] or [R]. R is from th[r]ee. C is from [1 A] [2 B] [3 C]. ?