Q: How many grams are there in 1 troy oz of 14K gold?

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There are about 31.1 grams in one troy ounce of 14k gold.

Precious metals are generally measured in troy ounces, so one troy oz of 14k gold is equal to 31.1 grams.

with gold at 1750 aprox. a troy ounce (31.8 grams) of PURE gold. 14K gold is 58.5% pure. So 1750 devied by 31.8 devied by .585 :)

3.336grams =about$40.32 worth of 14k

10 grams of 14k Gold is 10 grams.

the price of gold value is $1127.3652

For 24K Gold: 1 troy ounce = 31.10 grams 17.5 grams = .5627 troy ounces Multiply the price of gold by 0.5627 and you have your answer for 24KGold Example, if gold is worth $1700.00 USD per ounce, 17.5 grams = $956.59 USD ($1700*.05627=$956.59153) For 14K Gold (which is 14/24 pure) you must multiply this number by .5833. Example ($1700*.05627)*(.5833)=$557.98 WHY? Gold purity is measured on a scale of 24 karats. Pure Gold is 100% gold, or 24/24. 18 K gold is 75% gold (18/24) and 14K gold is not quite 60% gold. .5833 is the amount of gold in 14K gold (58.33% gold 41.67% not gold). 10K gold is 41.6% gold

The price of gold is based on a troy ounce which is approximately 31.1 grams. Try this site to get the current up to the minute price for gold http://www.kitco.com/charts/livegold.html. Remeber with 14k gold you need to multiply it by 58.3%. I would say you would get about $195, based on the current price of $15.00 per ounce of 14k gold.

I read somewhere that it takes about 1.77 or 1.74 ounces troy of 14k gold to make(smelter) out 1 ounce (troy) of 24k gold. I am trying to find the web site where I read that.. To get 10oz troy of 24k you would need around 17.4 to 17.7 oz troy of 14k

Multiply the total weight of the object in grams by 0.03215. Then multiple that result by the Karat weight of the item (14 in your example), and divide that total by 24. Example: 10 gram 14K ring x .03215 = .32 troy ounces total weight, x 14/24 = .19 troy ounces of gold

How much is 220 grams of gold worth

1 ounce = 28.34 grams 1 gram = 0.03 oz