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Which of the following electrolytes would you use to electroplate silver (Ag) on iron (Fe)?

agno3


What electrolytes would you use to electroplate silver Ag on iron Fe?

To electroplate silver Ag on iron Fe, you would need a silver nitrate solution as the source of silver ions (Ag+), and an iron (II) sulfate solution as the electrolyte to facilitate the exchange of ions during the electroplating process. You would also need a conducting material for the anode and cathode, along with an external power source to drive the electroplating reaction.


Formula silver nitrate?

The chemical formula for silver nitrate is AgNO3.


Chemical formula silver nitrate?

The chemical formula for silver nitrate is AgNO3.


What percent of AgNo3 is silver?

Silver nitrate (AgNO3) is composed of 63.5% silver by mass.


What is chemical symbol for silver nitrate?

Silver nitrate = AgNO3


What purpose does AgNo3 solution serve in Silver Chloride?

The silver nitrate solution (AgNO3) provides the silver in silver chloride.


What is the correct formula for silver (I) nitrate?

The correct formula for silver (I) nitrate is AgNO3.


What is the name of the chemical formula AgNO3?

Its name is silver nitrate octahydrate. silver(Ag) nitrite(NO2) * octahydrate (8H2O)


What ionic compound is AgNO3?

Can't say, since "o" is not an element. However: Ag3N is Silver Nitride AgNO2 - Silver Nitrite AgNO3 - Silver Nitrate


Mass of silver in 3.4g AgNO3?

To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of silver nitrate (AgNO3). The molar mass of AgNO3 is 169.87 g/mol. Since the molar ratio of Ag to AgNO3 is 1:1, the mass of silver in 3.4g of AgNO3 would be 3.4g * (1/169.87) ≈ 0.02g.


What is the mass of silver in 3.4g AgNo3?

To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. From this, you can calculate the mass of silver (Ag) in AgNO3, which is 107.87 g/mol. Therefore, the mass of silver in 3.4g of AgNO3 is (107.87/169.87) * 3.4g.