Na plus or Al 3plus, Al 3+ has greater coagulating power
Cl- or SO4^2- , SO4^2- has greater coagulating power.
Look at their net charges
Na+ has one charge
Al3+ has three
so Al3+ has greater coagulating power.
Cl- has one charge
SO4^-2 has two.
so SO4^2- has greater coagulating power
To determine the number of oxygen atoms in the reaction, we first need to identify the oxygen atoms in each compound. In 3CuSO4, there are 4 oxygen atoms per CuSO4 unit, contributing 12 oxygen atoms (3 × 4). In 2Ala12(SO4)3, each sulfate (SO4) has 4 oxygen atoms, so 2(SO4) contributes 8 oxygen atoms (2 × 4). Therefore, the total number of oxygen atoms in the reaction is 12 + 8 = 20 oxygen atoms.
The ion MnO4 is reduced toMnO2 and sulfur is oxidized to ion sulfate. Sulfite is the reducing agent.
Sulphate SO4 2-
The oxydation state for S in (SO4)2- is 6.
Fe(SO4)3 is Iron(III) sulfate Wrong: Fe2(SO4)3 is iron(III) sulfate.
Ammonium chloride
S in (SO4)-2 has a charge of +6, in SO2 S has a charge of +4. To go from +6 to +4 you must gain two electrons. The (SO4)-2 is reduced (reduction is gaining electrons). Therefore it reduces the 2br-, so (SO4)-2 is the reducing agent
3Ag2SO4 + 2AlCl3 -> 6AgCl + Al2(SO4)3
(NH4)2SO4
2In + 3H2SO4 --> In2(SO4)3 + 3H2
oxidation number of S is +6.It oxidize into SO4 ^-2
SO4 is not a molecule. (SO4)2- is the sulfate ion.
FeCl3 + H2O4-2 +Zn
To determine the number of oxygen atoms in the reaction, we first need to identify the oxygen atoms in each compound. In 3CuSO4, there are 4 oxygen atoms per CuSO4 unit, contributing 12 oxygen atoms (3 × 4). In 2Ala12(SO4)3, each sulfate (SO4) has 4 oxygen atoms, so 2(SO4) contributes 8 oxygen atoms (2 × 4). Therefore, the total number of oxygen atoms in the reaction is 12 + 8 = 20 oxygen atoms.
It is SO4 -2 named as sulphate ion.
Ba(SO4) + 2KCl
SO4 is the chemical formula for the anion sulfate.