Hydrogen (H2) will diffuse the fastest because it has the smallest molecular weight, which corresponds to higher average speeds of the gas particles at a given temperature. This allows hydrogen molecules to move more quickly through a medium compared to the heavier carbon dioxide (CO2) and methane (CH4) molecules.
CO2 (carbon dioxide) is chief among them, followed by CH4 (methane), N2O (nitrous oxide), and O3 (ozone).
The molecular equation for the combustion of methane gas (CH4) in the presence of oxygen (O2) is: CH4 + 2O2 -> CO2 + 2H2O.
Oxygen (O2) would diffuse from alveoli in the lungs into the blood, while carbon dioxide (CO2) would diffuse from the blood into the alveoli for elimination from the body during internal respiration.
The balanced equation for the reaction is: CH4 + 2O2 → CO2 + 2H2O. This balance was achieved by making sure the number of atoms of each element is the same on both sides of the equation.
Chlorine gas diffuses the fastest among the gases listed. This is because gases with lower molar masses diffuse faster, and chlorine gas has the lowest molar mass among the options provided.
Hydrogen (H2) will diffuse the fastest because it has the smallest molecular weight, which corresponds to higher average speeds of the gas particles at a given temperature. This allows hydrogen molecules to move more quickly through a medium compared to the heavier carbon dioxide (CO2) and methane (CH4) molecules.
CO2 diffuses faster than oxygen because it is a smaller molecule and has a lower molecular weight, allowing it to move more rapidly through cell membranes and other barriers. Additionally, CO2 has a higher solubility in water compared to oxygen, further aiding its diffusion.
The balanced equation for methane burning in oxygen to form water and carbon dioxide is: CH4 + 2O2 -> 2H2O + CO2
The balanced chemical equation for the reaction CH4 + 2O2 → CO2 + 2H2O shows that 1 molecule of CH4 reacts with 2 molecules of O2 to produce 1 molecule of CO2 and 2 molecules of H2O. This equation ensures that the number of atoms of each element is the same on both sides of the reaction arrow.
co2
The reaction represented by the equation CH4 + 2O2 -> CO2 + 2H2O yields carbon dioxide (CO2) and water (H2O) as products.
The equation for a complete combustion reaction of CH4 is : CH4 + 2 O2 = CO2 + 2 H2O, showing that one mole of carbon dioxide is formed for each mole of CH4 burned. Therefore, the answer is 44 moles of CO2 formed.
The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO21 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH40.0625 moles CH4 ==> 0.0625 moles CO20.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.
The balanced chemical equation for the reaction CH4 + 2O2 -> CO2 + 2H2O shows that one methane molecule (CH4) reacts with two oxygen molecules (O2) to produce one carbon dioxide molecule (CO2) and two water molecules (H2O).
When methane (CH4) reacts with oxygen (O2), it forms water (H2O) and carbon dioxide (CO2). The balanced chemical equation for this reaction is: CH4 + 2O2 -> CO2 + 2H2O.
Sulfur dioxide diffuses faster than CO2 because sulfur dioxide has a lighter molecular weight and a smaller size compared to CO2. This allows sulfur dioxide molecules to move more quickly and easily through a medium, resulting in faster diffusion rates.