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At NTP (standard temperature and pressure), which is 0 degrees Celsius and 1 atm pressure, the volume occupied by 1 gram of helium would be approximately 22.4 liters. This value is based on the ideal gas law and the molar mass of helium.
Well, density is a ratio. Therefore the density of the material would be 1g/mL .
100mg is a unit of mass, while liters are a unit of volume. To convert between the two, you would need to know the density of the substance in question. Without that information, it is not possible to directly convert 100mg to liters.
This question cannot be answered sensibly. A litre is a measure of volume, with dimensions [L3]. A kilogram is a measure of mass, with dimensions [M]. The two measure different things and basic dimensional analysis teaches that you cannot convert between measures with different dimensions such as these without additional information. As a simple mental exercise consider a litre of air and a litre of water. They will have very different masses.
Ok, this would be a problem of essentially displacement as the lift is caused by displacing "air".Ok, so one needs the densities of air and helium at some given temperature and pressure... "STP" is common, although one really would need to do it at the ambient temperature... or to do the final conversion using the simple formula PV=nRT.According to answers.yahoo.com, the densities of air and helium at STP are:Density of helium = 0.0001785 g/cm³Density of air = 0.001293 g/cm³,Ok, so your questions is how many cm³ of helium are needed to lift 1 gm.... let's try to make an equation.So, if we displace X cm³ of air with Helium we have:(X cm³)*(Density of Air g/cm³) - (X cm³)*(Density of Helium g/cm³) = (mass displaced in grams).Set the amount of mass being displaced to 1 gram, and putting in the densities we have:(X cm³)*(0.001293 g/cm³) - (X cm³)*(0.0001785 g/cm³) = 1 g(X cm³)*(0.001293 g/cm³ - 0.0001785 g/cm³) = 1 g(X cm³) = 1g/(0.001293 g/cm³ - 0.0001785 g/cm³)(X cm³) = 897 cm³You had asked in liters... with 1000 cm³/liter, the answer would be:0.897 liters of helium would displace 1 gram of oxygen without taking into account the weight of the container, or any pressure imposed by inflating container such as a rubber balloon.
One million molecules of water seems like a lot. But one mole of water contains 6.022 E 23 molecules of water, so one million molecules is only 1.66 E(-18) moles of water. This means that the volume is 2.99 E(-20) liters and has a mass of 0.299 femtograms.