It is the reverse: Np-235 decay to U-235 by electron capture.
Uranium has a different decay chain/series for its different isotopes. Uranium 238 for example first decays to thorium 234 through alpha decay while U235 alpha decays to thorium 231. Both have different half lifes which can be found on a natural decay series chart for the said element. The thorium in either case then beta decays to another element.
Atomic mass is conserved. Atomic number is NOT typically conserved in nuclear reactions. For example, when U235 spits out an alpha particle, its number drops by two (loss of two protons), and the mass by four, resulting in Thorium 231. The total mass is conserved, because the mass of the emitted alpha particle is 4.When an element decays by beta particle emission, the atomic number goes up by one, but the mass remains essentially the same. In spontaneous fission a pair of atoms reform with a spray of free neutrons. These neutrons have a half life of almost 15 minutes. If they bombard sufficiently heavy neighboring nuclei, what occurs is known as a fission chain reaction.
Yes, U233, U235, and U238 are all used as nuclear fuels.
You probably mean decays, not degrades. When an unstable atom decays it goes through one of the following processes:Alpha decay - a helium nucleus is ejected reducing the element number by 2 and the mass number by 4.Beta decay - a neutron decays to a proton, electron, and a neutrino. The electron and neutrino are ejected increasing the element number by 1 and leaving the mass number constant.Gamma decay - the protons and neutrons in the nucleus rearrange themselves into a lower energy state and a gamma ray photon is ejected to remove the excess energy. Neither the element or mass numbers change.Fission - certain transient metastable isotopes (e.g. U236 produced by U235 capturing a neutron) can split into two smaller nuclei and eject 2 or more neutrons. Note: Fission is not usually considered a decay process.
You get this answer by performing the following: Mass # Mass # 4 Atomic # Parent symbol -> Atomic # Daughter symbol + 2 He 238 234 4 92 U -> 90 Th + 2 He Both sides must equal the same thing, so if you figure out what plus 4 = 238 and what plus 2 = 92, you can figure out the element is formed through decay. The resulting element in this case is Thorium.
Uranium has a different decay chain/series for its different isotopes. Uranium 238 for example first decays to thorium 234 through alpha decay while U235 alpha decays to thorium 231. Both have different half lifes which can be found on a natural decay series chart for the said element. The thorium in either case then beta decays to another element.
I think you mean Pu-239, but we'll look at both Pu-239 and Pu-238 We'll compare to aspects, the decay energy and the fissile energy. First the decay energy. U235 alpha decays and releases 4.679 MeV in the process Pu238 alpha decays and releases 5.593 MeV Pu239 alpha decays and releases 5.245 MeV For the fissile energy. U235 fissiling releases 202.5 MeV Pu238 does not sustain a fissile, but the spontaneous fissile is 204.66 MeV Pu239 fissilings releases 207.1 MeV Pu238, because it does not sustain a fissile (though it does go through spontaneuos fissile) and because it does not emit much other stuff, other then the alpha particle, it works great as a nuclear battery. For example 8 oz of Pu238 will power the average laptop for about 29 years, without ever needing to be recharged or replaced.
Each time a U235 atom decays, it emits 2-3 neutrons. The likelihood that one of these neutrons is captured by another U235 atom INCREASES with more mass. The SHAPE of this mass will also play a role, imagine a thin wire of U235, compared to a sphere, with regards to how likely a chain reaction will occur. Neutron reflection can also help redirect an errant neutron back into the mass so it can react instead. Compression (increase of density) plays a role as well.
Atomic mass is conserved. Atomic number is NOT typically conserved in nuclear reactions. For example, when U235 spits out an alpha particle, its number drops by two (loss of two protons), and the mass by four, resulting in Thorium 231. The total mass is conserved, because the mass of the emitted alpha particle is 4.When an element decays by beta particle emission, the atomic number goes up by one, but the mass remains essentially the same. In spontaneous fission a pair of atoms reform with a spray of free neutrons. These neutrons have a half life of almost 15 minutes. If they bombard sufficiently heavy neighboring nuclei, what occurs is known as a fission chain reaction.
Element number 92 is Uranium and there are two main isotopes - U235 and U238. In U235 there are 92 protons so there are 235 - 92 = 143 neutrons. In U238 there are thus 146 neutrons
It is estimated that 1 kilogram of U235 can produce approximately 24,000 MWh of electricity in a nuclear reactor. This amount can vary depending on the efficiency of the reactor and the specific conditions of operation.
In power reactors the fuel is uranium enriched slightly to about 4 percent U235 (the fissile isotope), whereas for a bomb you need the U235 as high as possible, in the high 90's I believe.
Yes, U233, U235, and U238 are all used as nuclear fuels.
which process & which isotope u mention 1. nuclear reaction U235 & Pu239
2 different isotopes of uranium. isotope= element with same number of electrons, same number of protons, different numbers of neutrons. U235 has 143 neutrons and 92 protons U238 has 146 neurtons and 92 protons
The references I have state Oralloy is 93.5% U235. Oralloy (Oak Ridge Alloy) was used in US Uranium atomic bombs as the fissile material. However they also say that any enrichment 20% U235 or higher is fissile and could be used to make a bomb, it would require a higher critical mass to work though. One source I have states that early Soviet Uranium atomic bombs used ~97% U235, but the US felt this level of enrichment to be unnecessary and excessively expensive.
Enough of either U235 or PU239 to form a critical mass and hence a large explosion