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Answer for USA, Canada and countries running a 60 Hz supply service.

The motor's amperage has to be found to answer this question.

The formula to use is I = HP x 746/1.73 x E x %eff x pf.

A standard motor's efficiency between 5 to 100 HP is .84 to .91.

A standard motor's power factor between 10 to 100 HP is .86 to .92.

Amps = 746 x 1.5/1.73 x 480 x .84 x .86 = 1119/200 = 5.6 amps

The breaker has to be sizes to 250% of the motors full load amps. 5.6 x 250% = 14 amps.

A three pole 15 amp breaker connected to three conductor 600 volt rated cable will be needed.

As for overload protection without knowing the brand of contactor it is hard to say what the proper number of the heaters will be.

To obtain the proper overload protection base the overload heaters on the 5.6 amps or the motors full load amps that will be on the motor's nameplate.

As always, if you are in doubt about what to do, the best advice anyone should give you is to call a licensed electrician to advise what work is needed.

Before you do any work yourself,

on electrical circuits, equipment or appliances

always use a test meter to ensure the circuit is, in fact, de-energized.

IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOB

SAFELY AND COMPETENTLY

REFER THIS WORK TO QUALIFIED PROFESSIONALS.

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