The answer is 2,107749515.1025 molecules.
Chat with our AI personalities
Each mole of NH3 contains 1 mole of N. 35 grams N2 x 1mol N2/28g = 1.25 moles of N2 = 2.5 moles of N. This will make 2.5 moles NH3 (given sufficient H2 gas). The mass of NH3 would be
2.5 moles x 17 g/mole = 42.5 grams.
Avogadro's number, N, is the number of particles in one mole of a substance. N is approximately equal to 6.02 * 1023. This value is constant; it applies to the number of particles in any substance.
# of molecules = N * n (where n is the number of moles)
# of molecules = 6.02 * 1023 molecules/mole * 35 moles
# of molecules = 2.107 * 1025 molecules
To determine the grams of NH3 produced from 2.08 grams of N2, you need to set up a balanced chemical equation for the reaction. Assuming the balanced equation is N2 + 3H2 -> 2NH3, you would calculate the moles of N2, then use stoichiometry to find the moles of NH3 produced. Finally, convert moles of NH3 to grams using the molar mass of NH3.
To find the mass of 200 moles of NH3 (ammonia), you'll need to know the molar mass of NH3, which is approximately 17.03 g/mol. Multiply the molar mass by the number of moles to get the mass: 17.03 g/mol x 200 mol = 3406 g. Therefore, the mass of 200 moles of NH3 is 3406 grams.
The percent by mass of hydrogen in NH3 is 17.65%. This can be calculated by dividing the mass of hydrogen in NH3 by the total mass of NH3 and then multiplying by 100.
394.794 grams
16,45 g nitrogen are needed.