Avogadro's number, N, is the number of particles in one mole of a substance. N is approximately equal to 6.02 * 1023. This value is constant; it applies to the number of particles in any substance.
# of molecules = N * n (where n is the number of moles)
# of molecules = 6.02 * 1023 molecules/mole * 35 moles
# of molecules = 2.107 * 1025 molecules
To determine the grams of NH3 produced from 2.08 grams of N2, you need to set up a balanced chemical equation for the reaction. Assuming the balanced equation is N2 + 3H2 -> 2NH3, you would calculate the moles of N2, then use stoichiometry to find the moles of NH3 produced. Finally, convert moles of NH3 to grams using the molar mass of NH3.
To find the mass of 200 moles of NH3 (ammonia), you'll need to know the molar mass of NH3, which is approximately 17.03 g/mol. Multiply the molar mass by the number of moles to get the mass: 17.03 g/mol x 200 mol = 3406 g. Therefore, the mass of 200 moles of NH3 is 3406 grams.
The percent by mass of hydrogen in NH3 is 17.65%. This can be calculated by dividing the mass of hydrogen in NH3 by the total mass of NH3 and then multiplying by 100.
394.794 grams
16,45 g nitrogen are needed.
The molar mass of ammonia (NH3) is approximately 17.03 grams per mole.
The molecular mass of ammonia (NH3) is approximately 17.03 grams per mole.
The molar mass of NH3 is 17.03 g/mol. To find the mass of 3 moles of NH3, you would multiply the molar mass by 3. Therefore, the mass of 3 moles of ammonia would be 51.09 grams.
For this you need the atomic (molecular) mass of NH3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. NH3=16.0 grams100 grams NH3 / (16.0 grams) = 6.25 moles NH3
To find the mass in grams of 1.20x10^25 molecules of ammonia (NH3), you first calculate the molar mass of NH3 (17.031 g/mol). Then, divide the given number of molecules by Avogadro's number (6.022x10^23 molecules/mol) to find the number of moles, and finally, multiply the number of moles by the molar mass to get the mass in grams, which will be approximately 4.08x10^2 grams.
Molecules of ammonia? Will assume so. 4.2 X 1025 molecules NH3 (1 mole NH3/6.022 X 1023)(17.034 grams/1 mole NH3) = 1188 grams of ammonia ===================( could call it 1200 grams NH3 for significant figure correctness )
You can find the mass of one mole of each of the individual elements by looking at the mass numbers.So, 1 mole of:N=14gH=1gsince there are 3 H's the total mass of 1 mole NH3 is 14+3=17gYou then multiply the actual number of moles by the g's per mole:=> 17x2.11=35.87g
To find the number of molecules in 0.95 grams of SF6, you would first calculate the number of moles of SF6 using its molar mass. Then, using Avogadro's number, you can determine the number of molecules. Next, you would convert this number of molecules to the number of moles of NH3 using the mole ratio between NH3 and SF6. Finally, you would convert the moles of NH3 to grams using the molar mass of NH3 to find the mass needed.
The molar mass of ammonia (NH3) is 17.03 g/mol. Therefore, the mass of 3 moles of ammonia would be 51.09 grams (17.03 g/mol x 3 moles = 51.09 grams).
To find the mass of NH3 produced, first calculate the number of moles of NH3 using the given mass and the molar mass of NH3. Then, use the relationship between moles and mass (mass = moles x molar mass) to find the mass of NH3.
To find the grams of H2 needed, we first calculate the moles of NH3 using its molar mass. Then, we use the balanced chemical equation to determine the mole ratio of H2 to NH3. Finally, we convert moles of H2 to grams using its molar mass.
the molecular mass number of NH3 = 17 atomic mass no.of N=14 x 1 atom (present in the compound)=14 atomic mass of H= 1 x 3 atoms (present in compound)=3 thus, molecular mass= atomic mass of N+ atomic mass of H3 = 14 + 3 = 17