1 mole of gas occupies 22.4 L at STP. So 56/22.4 = 2.5 moles. Neon has Atomic Mass of 20 and so 2.5 moles x 20 atomic weight = 50 so the mass is 50g.
Well, isn't that a happy little question! At standard temperature and pressure (STP), one mole of any gas occupies about 22.4 liters of space. So, for 0.05 moles of neon gas at STP, the volume would be 0.05 moles multiplied by 22.4 liters/mole, giving us 1.12 liters. Just imagine all that neon gas peacefully floating around in that volume, creating a lovely little atmosphere!
The molar mass of neon gas is approximately 20.18 g/mol. Therefore, the mass of 1 mole of neon gas is 20.18 grams.
The molar volume of a gas at STP (standard temperature and pressure) is 22.4 L/mol. To calculate the molar mass of the gas, you can use the formula: Molar mass = (mass of gas / volume of gas) x molar volume at STP. In this case, with a mass of 60g and a volume of 5.6 dm3, the molar mass would be 60g/5.6dm3 x 22.4L/mol = 240 g/mol. Vapour density is calculated as 2 x molar mass, so in this case the vapour density would be 480 g/mol.
At standard temperature and pressure (STP), the molar volume of a gas is approximately 22.4 L. To find the volume of 150g of ozone (O3) at STP, you would first convert the mass of ozone to moles, then use the molar volume to find the volume.
1 mol of any gas has a volume of 22.4 L at STP
The volume of 0.0100 mol of CH4 gas at STP (Standard Temperature and Pressure) is 224 mL. This is based on the ideal gas law and the molar volume of a gas at STP, which is 22.4 L/mol. Converting this to milliliters gives 224,000 mL/mol.
Well, isn't that a happy little question! At standard temperature and pressure (STP), one mole of any gas occupies about 22.4 liters of space. So, for 0.05 moles of neon gas at STP, the volume would be 0.05 moles multiplied by 22.4 liters/mole, giving us 1.12 liters. Just imagine all that neon gas peacefully floating around in that volume, creating a lovely little atmosphere!
The molar volume of an ideal gas at standard temperature and pressure (STP) is 22.4 L/mol. Therefore, 0.75 mol of methane gas would occupy 16.8 liters (0.75 mol x 22.4 L/mol = 16.8 L).
There are approximately 1.52 x 10^22 atoms of neon gas in 0.251 mol of Ne.
Using the ideal gas law, PV = nRT, we can calculate the number of moles of neon gas. Rearranging the formula gives n = PV / RT. Plugging in the values, n = (4.6 atm * 0.84 L) / (0.0821 L atm/mol K * 222 K) β 0.182 moles of neon gas.
The molar volume of a gas at standard temperature and pressure (STP) is 22.4 L/mol. Therefore, the volume of 2 moles of oxygen gas at STP would be 2 moles * 22.4 L/mol = 44.8 L.
The volume is 22,1 L.
Hydrogen gas is the lightest among neon, hydrogen, and carbon dioxide. Hydrogen gas has a molecular weight of 2 g/mol, while neon has a molecular weight of 20 g/mol and carbon dioxide has a molecular weight of 44 g/mol.
The volume of 0.44 mol of C2H6 gas at standard temperature and pressure (STP) is approximately 9.9 L. This is based on the molar volume of a gas at STP, which is around 22.4 L/mol.
If both gases are at the same conditions of temperature, pressure, and volume, then the number of moles of neon and xenon in the container would be the same. Since xenon is a heavier gas than neon, the container would hold less xenon by mass compared to neon for the same number of moles. Neon's molar mass is 20.18 g/mol, while xenon's molar mass is 131.29 g/mol, suggesting the container would hold less xenon by mass compared to neon.
The molar mass of neon gas is approximately 20.18 g/mol. Therefore, the mass of 1 mole of neon gas is 20.18 grams.
To find the volume of 19.87 mol of NHβCl at STP (standard temperature and pressure), we can use the ideal gas law. At STP, 1 mol of gas occupies 22.4 L. Therefore, 19.87 mol of NHβCl will occupy 19.87 mol x 22.4 L/mol = 445.888 L.