-1.68
-1.68 V
Aluminium (Al3+) has a similar electron configuration to the noble gas neon (Ne). Both Al3+ and Ne have a full outer electron shell, making them stable and unreactive.
In a standard galvanic cell using zinc and aluminum, the zinc metal will act as the anode and the aluminum metal will act as the cathode. Zinc will undergo oxidation at the anode, releasing electrons which flow through the external circuit to the cathode where aluminum will undergo reduction. This flow of electrons creates an electrical current.
Al3+
Al2O3
-1.68 V
-1.68 V
-1.68 V
- .92 V
3Ag2S + 2Al(s) ==> Al2S3 + 6 Ag(s)Ag^+ + e- ===> Ag(s) reduction @ cathode Eº=0.80 VAl ===> Al^3+ + 3e- oxidation @ anode Eº=-1.66 VOverall potential = Eºcell = 0.80 - (-1.66) = 2.46 V
The chemical formula for Al3 is Al3+ which represents an aluminum ion with a charge of +3. The chemical formula for CH3COO is C2H3O2-, which represents the acetate ion.
Al3 - Aluminum cationCN-Cyanide ion
Al | Al^3+ Zn^2+ | Zn
Au(s) | Au+(aq) Al3+(aq) | Al(s)(-_^)
Al(s) | Al3+(aq) Ni2+(aq) | Ni(s)
The compound formed between Al3+ and I- ions is aluminum iodide.
Type your answer here... Al(s) | Al3+(aq) Mg2+ (aq) | Mg(s)