-1.68
-1.68 V
The standard reduction potential (E°) for the half-reaction ( \text{Al}^{3+} (aq) + 3e^- \rightarrow \text{Al}(s) ) is approximately -1.66 V. This negative value indicates that the reduction of aluminum ions to aluminum metal is not favorable under standard conditions. Therefore, aluminum is more likely to oxidize than to be reduced.
The standard reduction potential (E°) for the half-reaction ( \text{Al}^{3+} + 3e^- \rightarrow \text{Al} ) is approximately -1.66 V. This negative value indicates that the reduction of aluminum ions to aluminum metal is not favorable under standard conditions. Consequently, aluminum tends to oxidize rather than reduce, making it an effective reducing agent in many chemical reactions.
Al3+ is isoelectronic with neon with 10 electrons
In a standard galvanic cell using zinc and aluminum, the zinc metal will act as the anode and the aluminum metal will act as the cathode. Zinc will undergo oxidation at the anode, releasing electrons which flow through the external circuit to the cathode where aluminum will undergo reduction. This flow of electrons creates an electrical current.
-1.68 V
-1.68 V
-1.68 V
- .92 V
3Ag2S + 2Al(s) ==> Al2S3 + 6 Ag(s)Ag^+ + e- ===> Ag(s) reduction @ cathode Eº=0.80 VAl ===> Al^3+ + 3e- oxidation @ anode Eº=-1.66 VOverall potential = Eºcell = 0.80 - (-1.66) = 2.46 V
The chemical formula for Al3 is Al3+ which represents an aluminum ion with a charge of +3. The chemical formula for CH3COO is C2H3O2-, which represents the acetate ion.
Al | Al^3+ Zn^2+ | Zn
Al3 - Aluminum cationCN-Cyanide ion
Au(s) | Au+(aq) Al3+(aq) | Al(s)(-_^)
Al(s) | Al3+(aq) Ni2+(aq) | Ni(s)
The compound formed between Al3+ and I- ions is aluminum iodide.
Type your answer here... Al(s) | Al3+(aq) Mg2+ (aq) | Mg(s)