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I figure anywhere between 20 and 100 N/m. Someone correct me if I'm wrong on the answer, but no one will answer this with an example of the force it would take, only formulas.

If you think about it, 1 newton would take you about 2-5 cm, which would equate to [k=F/x] k=1N/0.02, resulting in k=50 N/m. That equation is saying if you would take a meter-long pen spring, it would take 50 neutons to compress it completely. Hope this helps.

- Fellow physics student

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12y ago
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4mo ago

The spring constant of an average ballpoint pen spring is typically around 10-20 N/m, although it can vary depending on the specific design and manufacturer of the pen.

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Q: What is the spring constant of an average ball point pen spring?
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