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Assuming the lamps are plugged into a 60 volt outlet, the 40 W lamp has more resistance. This can be shown mathematically:

Resistance= V2/P=602/40=3600/40=90 ohms (40 Wlamp)

Resistance= V2/P=602/60=3600/60=60 ohms (60 Wlamp)

This shows that 40W lamp has more resistance than a 60W lamp.

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14y ago
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4mo ago

Assuming the bulb operates at a standard voltage of 120V, you can use the formula P=V^2/R to calculate the resistance. Rearranging the formula, R = V^2/P, R = 120^2 / 60 = 240 ohms. The resistance of a 60 watt bulb operating at 120V is approximately 240 ohms.

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13y ago

Did you buy it in Europe or in North America ?

In North America, it's expecting to be powered by 120 volts.

In most of the rest of the world, it expects 240 volts.

120 volts, 60 watts:

P = E2 / R

R = E2 / P = (120)2 / 60 = 240 ohms

240 volts, 60 watts:

R = E2 / P = (240)2 / 60 = 960 ohms.

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11y ago

Yes, it consumes about 33% less provided both bulbs are of the same type. It consumes less because the current is less.

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The power of a lamp, in watts, is the rate at which it consumes energy -so, obviously, a 40-W lamp will consume less energy over a given period of time than a 60-W lamp -in the same way as you will travel less far at 40 km/h than you would at 60- km/h!

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15y ago

The 40 watt bulb will for sure, you can find this out using simple watts and ohms laws. P=VC and V=RC where P=power V=voltage R=resistance and C=current.

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11y ago

The formulas you are looking for is R = E squared/W or R = W/I squared

For 60W@12V the resistance is 2.4 Ohms

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Q: What is the resistance on a 60 watt bulb?
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