The partial pressure of hydrogen gas can be calculated by subtracting the partial pressure of helium from the total pressure. Therefore, the partial pressure of hydrogen gas would be 161 mm Hg (600 mm Hg - 439 mm Hg = 161 mm Hg).
To convert Torr to mm Hg, divide by 1.33. So, the partial pressure of helium in mm Hg is 439 Torr / 1.33 = 330 mm Hg. To find the partial pressure of hydrogen, subtract the partial pressure of helium from the total pressure: 600 mm Hg - 330 mm Hg = 270 mm Hg. Hence, the partial pressure of hydrogen gas is 270 mm Hg.
The partial pressure of a gas in a mixture is equal to the total pressure of the mixture multiplied by the mole fraction of that gas. Since the mole fraction of O2 in air is 0.2084 and the total pressure of air is approximately 1 atmosphere, the partial pressure of O2 in air is approximately 0.2084 atmosphere.
If the temperature is increased, the partial pressure of oxygen in a sample of air will also increase. This is because as the temperature rises, the oxygen molecules in the air will have greater kinetic energy and will exert more pressure.
The partial pressure of water (vapor) is included in the total pressure of the atmosphere (air) when boiling.
The partial pressure of hydrogen gas can be calculated by subtracting the partial pressure of helium from the total pressure. Therefore, the partial pressure of hydrogen gas would be 161 mm Hg (600 mm Hg - 439 mm Hg = 161 mm Hg).
To convert Torr to mm Hg, divide by 1.33. So, the partial pressure of helium in mm Hg is 439 Torr / 1.33 = 330 mm Hg. To find the partial pressure of hydrogen, subtract the partial pressure of helium from the total pressure: 600 mm Hg - 330 mm Hg = 270 mm Hg. Hence, the partial pressure of hydrogen gas is 270 mm Hg.
Total pressure = ppO2 + ppH2 + ppN2ppN2 = Total pressure - (ppO2 + ppH2)ppN2 = 282 kPa - (110+106 kPa) = 282kPa - 216kPappN2 = 66 kPa = partial pressure of nitrogen
The partial pressure of a gas in a mixture is equal to the total pressure of the mixture multiplied by the mole fraction of that gas. Since the mole fraction of O2 in air is 0.2084 and the total pressure of air is approximately 1 atmosphere, the partial pressure of O2 in air is approximately 0.2084 atmosphere.
When the air temperature increases, the partial pressure of oxygen remains the same in the air. This is because the partial pressure of a gas in a mixture is determined by its concentration and is independent of the temperature, assuming the volume and moles of other gases remain constant.
The statement that is true is: The partial pressure of nitrogen is equal to the partial pressure of hydrogen in the box. This is because both nitrogen and hydrogen behave ideally and occupy the same volume, so their partial pressures are directly proportional to their mole quantities in the box.
If the temperature is increased, the partial pressure of oxygen in a sample of air will also increase. This is because as the temperature rises, the oxygen molecules in the air will have greater kinetic energy and will exert more pressure.
The partial pressure of water (vapor) is included in the total pressure of the atmosphere (air) when boiling.
The partial pressure of oxygen can be calculated by multiplying the percentage of oxygen in the air by the total pressure. In this case, 20 percent of 6.3 ATM is 1.26 ATM. Therefore, the scuba diver is breathing oxygen at a partial pressure of 1.26 ATM.
The pressure is 103,5 at.
The partial pressure of nitrogen in air at atmospheric pressure (1 atm) is approximately 0.78 atm. This means that nitrogen makes up about 78% of the total atmospheric pressure at sea level.
The partial pressure of oxygen is a measure of the pressure exerted by oxygen in a mixture of gases. In atmospheric air at sea level, the partial pressure of oxygen is around 160 mmHg. The partial pressure of oxygen can also be calculated using the equation: partial pressure of oxygen = total pressure of gas mixture * mole fraction of oxygen gas in the mixture.