The molarity is 2 mol/L.
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
The molarity is 6 mol/l.
The molarity is 0,041
The molarity of the solution is calculated by dividing the moles of solute (0.250 mol NaCl) by the liters of solution (2.25 L). Molarity = moles of solute / liters of solution Molarity = 0.250 mol / 2.25 L = 0.111 M
Molarity= moles/Liters To change grams to moles you divide by the mole weight which is listed on the periodic table. Mol= grams/mol weight The Mole weight of Magnesium Chloride is 59.8 grams/mol Mol=128g/59.8 Mol=2.14 Now, you put the number of moles and Liters into the equation Molarity=2.14 mol/1L Molarity=2.14 So, the molarity is 2.14 M
molarity is #moles divide by # liters, so 3.0 divided by 0.500 is 6.0 molarity (2 siginficant figures is all you are allowed)
2 m is the molarity of a solution that has 6 mol of CaCl2 in 3 km of water.
First, calculate the molar mass of CaCl2, which is 110.98 g/mol. Next, calculate the number of moles of CaCl2 in 330 grams using the formula moles = mass / molar mass. This gives you 2.97 mol of CaCl2. Finally, divide the moles of CaCl2 by the volume of the solution in liters to get the molarity, which is 2.97 M.
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
The molarity of a solution with 3 mol of glucose in 6 kg of water cannot be determined without knowing the volume of the solution. Molarity is defined as the amount of solute (in mol) divided by the volume of the solution in liters. Without the volume, the molarity of the solution cannot be calculated.
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, the molality of the CaCl2 solution would be 2 mol/kg, as 6 mol of CaCl2 dissolved in 3 kg of water results in a molality of 2 mol/kg.
To make a 0.2 M CaCl2 solution with a final volume of 200 ml, you would need to dissolve 8.8 grams of calcium chloride (CaCl2) in water. This calculation is based on the molar mass of CaCl2 (110.98 g/mol) and the formula for calculating molarity (moles = molarity x volume in liters).
2 m
4 mol/0.800 kg
molarity = moles/litre [solution] = 12 mol/6 L [solution] = 2 mol/L = 2 M
No, adding water to a solution does not change the molarity of the solute. The molarity of a solution is calculated using the amount of solute and the volume of the solution, so diluting with water only changes the volume, not the amount of solute present.
The molarity is 6 mol/l.