To determine the number of moles in 1 g of zinc nitrate, you need to know the molar mass of zinc nitrate. Zinc nitrate has a molar mass of 189.36 g/mol. By dividing 1 g by the molar mass, you can calculate that there are approximately 0.0053 moles of zinc nitrate in 1 g.
The molar mass of anhydrous iron(II) nitrate is 179,91 g.
To make You need the molar mass of Silver nitrate to make 0.1 Silver Nitrate.
First, determine the molar mass of magnesium nitrate (Mg(NO3)2) by adding the atomic masses of magnesium, nitrogen, and oxygen. Then, divide the given mass (9.00g) by the molar mass to find the moles of magnesium nitrate.
The molecular mass of sulfuric acid (H2SO4) is 98.08 g/mol and the molecular mass of potassium nitrate (KNO3) is 101.10 g/mol.
The molar mass of ammonium nitrate (NH4NO3) is approximately 80.04 g/mol.
169.8731 g/mol
To determine the number of moles in 1 g of zinc nitrate, you need to know the molar mass of zinc nitrate. Zinc nitrate has a molar mass of 189.36 g/mol. By dividing 1 g by the molar mass, you can calculate that there are approximately 0.0053 moles of zinc nitrate in 1 g.
The molar mass of anhydrous iron(II) nitrate is 179,91 g.
The molar mass of potassium nitrate is 101,1032 g.
To find the number of moles in 1.25 grams of iron nitrate, we need to know its molar mass. Iron nitrate has a molar mass of approximately 404.0 g/mol. By dividing the mass by the molar mass, we find that 1.25 grams of iron nitrate is roughly 0.0031 moles.
Molar mass of KNO3 is 101gmol-1. This is a neutral compound.
To find the number of moles in 8.0g of ammonium nitrate, you need to divide the given mass by the molar mass of ammonium nitrate (NH4NO3). The molar mass of NH4NO3 is 80.05 g/mol. Therefore, 8.0g ÷ 80.05 g/mol = 0.1 moles of ammonium nitrate.
The molar mass of silver nitrate (AgNO3) is approximately 169.87 g/mol. Multiplying this by 2 gives a molar mass of 339.74 g/mol for 2 moles of AgNO3.
To make You need the molar mass of Silver nitrate to make 0.1 Silver Nitrate.
The molar mass of aluminum nitrate (Al(NO3)3) is 213 g/mol. The molar mass of nitrogen in the compound is 14 g/mol. Therefore, the percentage by mass of nitrogen in aluminum nitrate is (3 * 14) / 213 * 100 ≈ 19.7%.
The molar mass of calcium nitrate is 164.1 g/mol. The molar mass of nitrogen is 14.01 g/mol. So, the percentage of nitrogen in calcium nitrate is (14.01 g/mol / 164.1 g/mol) * 100% ≈ 8.54%.