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The gram formula mass for KI or potassium iodide is 166.0027 grams per mole. You find this mass by multiplying the atomic masses of potassium and iodine by the number of atoms given for each in the formula, and then adding these two results.

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What is the molar mass for potassium iodide?

The molar mass for potassium iodide is 166,0028.


What mass of KI is present in 276 mL of a 0.50 M solution?

To calculate the mass of KI in the solution, first calculate the number of moles of KI present using the formula moles = Molarity x Volume (in liters). Then, use the molar mass of KI (potassium iodide) to convert moles to grams. The molar mass of KI is 166 g/mol.


What is the percent composition of potassium in potassium iodide Kl?

The percent composition of potassium in potassium iodide (KI) is 58.5%. This is calculated by dividing the atomic mass of potassium by the molar mass of KI and multiplying by 100.


How many grams of KI are required to prepare 500ml of 0.04 M KI?

To calculate the grams of KI required, use the formula: grams = molarity (M) × volume (L) × molar mass (g/mol). The molarity is 0.04 M and the volume is 0.5 L (500 ml). The molar mass of KI is approximately 166 g/mol. Therefore, grams of KI required = 0.04 M × 0.5 L × 166 g/mol = 3.32 grams.


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What is the molarity of 820mL of Kl solution that contains 36.52g of Kl?

To find the molarity (M) of the KI solution, first convert grams of KI to moles using its molar mass (KI's molar mass is approximately 166 g/mol). Moles of KI = 36.52 g / 166 g/mol ≈ 0.220 moles. Then, convert the volume from mL to liters: 820 mL = 0.820 L. Finally, calculate the molarity: M = moles/volume = 0.220 moles / 0.820 L ≈ 0.268 M. Thus, the molarity of the KI solution is approximately 0.268 M.


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