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∙ 11y ago0.40 moles of aspirin is 72.1 g.
Wiki User
∙ 9y agoFirst, calculate the molar mass of aspirin (C9H8O4) using the Periodic Table. Next, convert the number of molecules to moles by dividing by Avogadro's number. Finally, multiply the number of moles by the molar mass of aspirin to find the mass in grams.
Wiki User
∙ 11y agoThe gram molecular mass of any compound with the formula C9H8O4 is [9(gram Atomic Mass of carbon) + 8(gram atomic mass of hydrogen ) + 4(gram atomic mass of oxygen)] or 180.1558. This by definition is the mass of Avogadro's Number of molecules. Therefore the mass of 1.40 X 1021 molecules is:
180.1558[(1.40 X 1021 )/6.022 X 1023)] or 4.19 X 10-1 grams, to the justified number of significant digits.
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∙ 9y ago1.56 moles of Aspirin is equal to 281 grams.
Wiki User
∙ 7y agoThe molar mass of aspirin (2-acetoxybenzoic acid), C9H8O4, is 180.157 g/mol.
Wiki User
∙ 7y agoC9H18O4 has a molar mass of 180.157 g/mol
Rongeline Cajuelan
72
im sorry its 10 to the 21 power
Assuming that this ammonia gas is at STP, you can use Avogadro's number to gind the number of moles of gas:(387 x 1021 molecules) x (1 mol / 6.02x1023particles) x (17.03 g / 1 mol) =110 g NH3
0.015 x 6.022 x 1023 = 9.033 x 1021
First, calculate the molar mass of O2 (molecular weight = 32 g/mol). Then, convert the given number of molecules to moles using Avogadro's number (6.022 x 10^23 molecules/mol). The result would be approximately 0.067 moles of O2.
0.5 carat carbon (0.2 grams/1 carat)(1 mole C/12.01 grams)(6.022 X 1023/1 mole C) = 5.0 X 1021 atoms of carbon ===================
im sorry its 10 to the 21 power
To convert from molecules to moles, you divide the number of molecules by Avogadro's number (6.022 x 10^23). So, for 4.3 x 10^21 molecules of UF6, you would have approximately 0.0071 moles of UF6.
4.51 g x 1 mol x 6.022 x 1023 molecules = 9.95 x 1021 molecules .............273 g ............... 1 mol
Assuming that this ammonia gas is at STP, you can use Avogadro's number to gind the number of moles of gas:(387 x 1021 molecules) x (1 mol / 6.02x1023particles) x (17.03 g / 1 mol) =110 g NH3
7.40025*1021 approx.7.40025*1021 approx.7.40025*1021 approx.7.40025*1021 approx.
0.015 x 6.022 x 1023 = 9.033 x 1021
To calculate the number of molecules of N2 gas, we need to use the ideal gas law. We first convert the volume to liters by dividing 500.0 ml by 1000. Then, we use the formula PV = nRT to find the number of moles of N2 gas in the sample. Finally, we multiply the number of moles by Avogadro's number (6.022 x 10^23) to find the number of molecules.
1021 = MXXI
1021 is a prime number. Therefore, its only positive integer factors are 1 and 1021.
Not by anything other than 1 or 1021. 1021 is a prime number.
The sum is: 9+1021 = 1030
First, calculate the molar mass of O2 (molecular weight = 32 g/mol). Then, convert the given number of molecules to moles using Avogadro's number (6.022 x 10^23 molecules/mol). The result would be approximately 0.067 moles of O2.