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I'm not sure, but my guess is: W(C2O4)5(HO4)4
Since Tungsten symbol is W and has a variable charge of 5.
Oxylate is C2O4 and will put the variable charge of tungsten after the parenthesis of oxylate (C2O4)5.
And since, "hydrate" symbol is HO4 and has a prefix of "tetra", it will now written as (HO4)4
Formula: W(C2O4)5 (HO4)4
Feel free to correct my answer co'z I'm not sure.
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CoachTo calculate the formula weight of tungsten V oxalate tetrahydrate, you would add the atomic weights of each element in the compound (W, C, H, O). The formula weight would be the sum of the atomic weights multiplied by the number of atoms of each element in the compound. You would also need to account for the four water molecules (H2O) in the compound.
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The atomic number of tungsten (W) is 74.The atomic weight of W is 183.84 grams per mole.See the Web Links to the left of this answer for a periodic table with more information about this element!
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To calculate the empirical formula from a molecular formula, divide the subscripts in the molecular formula by the greatest common factor to get the simplest ratio of atoms. This simplest ratio represents the empirical formula.
