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Where does the heat energy go when ice at 0 and degc melts to form water at 0 and degc?

When ice at 0°C melts to form water at 0°C, the heat energy supplied goes into breaking the hydrogen bonds between the water molecules in the ice. This process is called latent heat of fusion, and it does not raise the temperature of the substance; instead, it changes the state from solid to liquid. The temperature remains constant at 0°C until all the ice has melted.


Does uranium boil or melt?

Melting point 1132 degC, boiling point 4131 degC


What water does at 100 and degc?

It boils


What would happen to a sample of water at 30 and degC if it is heated until the temperature reaches 120 and degC?

Water is transformed in vapors.


If a liquid sample of naphthalene is heated and remains at 218 and degC until it is completely vaporized you know that 218 and degC is the of naphthalene.?

Boiling point.


At 30 and degC what state is bromine in?

Liquid


When A balloon has a volume of 10500 liters and the temperature is 15 and degC. If the temperature were -25 and degC what would the volume of the balloon be?

It would be approx 9042 litres.


The specific heat of a certain type of cooking oil is 1.75 cal(g and middot and degC). How much heat energy is needed to raise the temperature of 2.40 kg of this oil from 23 and degC to 191 and degC?

The change in temperature is ΔT = 191°C - 23°C = 168°C. The heat energy Q required is given by the formula Q = mcΔT, where m is the mass, c is the specific heat, and ΔT is the temperature change. Plugging in the values: Q = 2.4 kg * 1.75 cal/(g°C) * 168°C = 7056 cal = 7.056 kcal.


What is the change in thermal energy of the air when it warms from 24 and degC to 31 and degC?

The change in thermal energy can be calculated using the formula: ( Q = mc\Delta T ), where ( Q ) is the change in thermal energy, ( m ) is the mass of the air, ( c ) is the specific heat capacity of air, and ( \Delta T ) is the change in temperature. The specific heat capacity of air is approximately 1000 J/kg°C. Assuming the mass is 1 kg, the change in thermal energy would be ( Q = 1kg \times 1000 J/kg°C \times 7°C = 7000 J ).


The volume of a gas is 605 liters at 27.0 and degC. The new temperature is -3.0 and degC. What is the new volume (Remember to convert temperatures to the Kelvin scale.)?

The new volume is 544,5 l.


If I dissolve 50 grams of salt in 1000 mL of water and the temperature decreases from 30.5 and degC to 35.6 and degC what is the heat change enthalpy of reaction Was this an exothermic or endothermic?

How can the temperature DECREASE from 30.5ºC to 35.6ºC? That's an INCREASE in temperature. So, assuming you meant the temperature INCREASED to 35.6ºC, then it is an endothermic reaction.q = mC∆T = (1000 g)(4.184 J/g/deg)(5.1 deg) = 20,920 J = 20.9 kJ. This is the heat change for this reaction.


What would happen to the solubility of potassium chloride in water as the water temperature increased from 25 and degC to 100 and degC?

The solubility increase from 38,7 g KCl/100g water to 40,7 g KCl/100 g water.