Delta S= Delta H
When ice at 0°C melts to form water at 0°C, the heat energy supplied goes into breaking the hydrogen bonds between the water molecules in the ice. This process is called latent heat of fusion, and it does not raise the temperature of the substance; instead, it changes the state from solid to liquid. The temperature remains constant at 0°C until all the ice has melted.
Melting point 1132 degC, boiling point 4131 degC
It boils
The new volume is 544,5 l.
The solubility increase from 38,7 g KCl/100g water to 40,7 g KCl/100 g water.
When ice at 0°C melts to form water at 0°C, the heat energy supplied goes into breaking the hydrogen bonds between the water molecules in the ice. This process is called latent heat of fusion, and it does not raise the temperature of the substance; instead, it changes the state from solid to liquid. The temperature remains constant at 0°C until all the ice has melted.
Melting point 1132 degC, boiling point 4131 degC
It boils
Water is transformed in vapors.
Boiling point.
Liquid
It would be approx 9042 litres.
The change in temperature is ΔT = 191°C - 23°C = 168°C. The heat energy Q required is given by the formula Q = mcΔT, where m is the mass, c is the specific heat, and ΔT is the temperature change. Plugging in the values: Q = 2.4 kg * 1.75 cal/(g°C) * 168°C = 7056 cal = 7.056 kcal.
The change in thermal energy can be calculated using the formula: ( Q = mc\Delta T ), where ( Q ) is the change in thermal energy, ( m ) is the mass of the air, ( c ) is the specific heat capacity of air, and ( \Delta T ) is the change in temperature. The specific heat capacity of air is approximately 1000 J/kg°C. Assuming the mass is 1 kg, the change in thermal energy would be ( Q = 1kg \times 1000 J/kg°C \times 7°C = 7000 J ).
The new volume is 544,5 l.
How can the temperature DECREASE from 30.5ºC to 35.6ºC? That's an INCREASE in temperature. So, assuming you meant the temperature INCREASED to 35.6ºC, then it is an endothermic reaction.q = mC∆T = (1000 g)(4.184 J/g/deg)(5.1 deg) = 20,920 J = 20.9 kJ. This is the heat change for this reaction.
The solubility increase from 38,7 g KCl/100g water to 40,7 g KCl/100 g water.