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The half life of C-14 is about 5730 years and 12.5% is 100% x (.5)^3 so 3 half lives of the C-14 have occured. Now all you do is multiply 5730 years by 3 and get 17190 years. That's pretty old!

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An artifact is found that some are claiming is 30000 years old 3.1 percent of the original carbon14 is present The halflife of carbon14 is 5730 year?

To determine the age of the artifact, you can use the formula for exponential decay of radioactive elements: (N = N_0 \times (1/2)^{t/T}), where N is the final amount (3.1% of the original), N0 is the initial amount (100%), t is the time passed, and T is the half-life (5730 years). By substituting the values, you can solve for t, which will give you the age of the artifact.


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Related Questions

An artifact is found that some are claiming is 30000 years old 3.1 percent of the original carbon14 is present The halflife of carbon14 is 5730 year?

To determine the age of the artifact, you can use the formula for exponential decay of radioactive elements: (N = N_0 \times (1/2)^{t/T}), where N is the final amount (3.1% of the original), N0 is the initial amount (100%), t is the time passed, and T is the half-life (5730 years). By substituting the values, you can solve for t, which will give you the age of the artifact.


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