F=ma
a=F/m
a=7500/1500
a=5m/s^2
force = mass x accel = 1800 x 3 = 5400 Newtons
An example of Newton's second law is that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This means that a heavier object requires more force to accelerate at the same rate as a lighter object.
While the forces between the truck and trailer are equal in magnitude and opposite in direction, they act on different objects (truck and trailer) resulting in acceleration of the entire system. The truck exerts a force on the trailer causing it to accelerate forward, and in return, the trailer exerts an equal and opposite force on the truck. As both objects have different masses, this results in them accelerating in the direction of the larger force, which is from the truck to the trailer.
Isaac Newton's second law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically, this can be expressed as F = ma, where F is the net force, m is the mass of the object, and a is the acceleration.
since a=f/m if you want to flow in traffic with a big mass you need a big force to match acceleration of other vehicles
The force required is 70,310 newtons.
1697
The force required to lift a truck into the air depends on the weight of the truck. You can calculate the force needed by using the formula Force = Mass x Acceleration (where acceleration is typically g = 9.81 m/s^2).
The work done by a truck pulling a trailer for a distance of 100 M while exerting a force of 480 newtons is 48000 newtons.
Force = mass * acceleration and acceleration is in units of meters per second squared. I will assume you mean this. m/s2 Force = (1800 kg)(4 m/s2) = 7200 Newtons ----------------------
the truck and the insect have the same amount of force....Newtons third law
Force = mass * acceleration Force = (3000 kg)*(2 m/s^2) = 6000 Newtons ---------------------- ( that is 6000 times the force needed to push in a doorbell, on average )
If there is no change in force as the mass of a truck increases, then its acceleration decreases. This is because the acceleration of an object is inversely proportional to its mass when force is kept constant (Newton's second law, F=ma). Therefore, as the mass increases, the acceleration decreases.
The answer is: any force equal to or greater than the forward momentum of the truck. So many variables enter into calculating a precise measurement of force needed to stop a vehicle - mass of the vehicle, conditions of friction and gravity - is the truck going uphill or downhill, or on a flat surface? Is the road slippery, smooth or rough? Let's assume that normal conditions apply: a truck weighing 10,000 Kg traveling at an acceleration rate of 5m/s² along a flat smooth surface. Using Newton's second Law of Motion, expressed as a formula F=ma, where F is the Net Force (the sum of all forces acting on an object) in Newtons, m is the mass of the truck, and a is its acceleration rate, assumed here to be 5m/s². By multiplying the mass times acceleration, we see that a whopping 50,000 Newtons would be required to stop this truck. By comparison, the pull of gravity on a person of average weight (72 Kg, or 160 lb) is measured at 686 Newtons. So depending on the type of truck, weather conditions, wind speed, direction of the truck, and effect of gravity and friction (all included in net force, or Newtons) you can see that the actual Force, expressed as N, is a variable.
To calculate the mass of the truck, you can use the formula: mass = force / acceleration. Substituting the given values, the mass of the truck would be 14000 N / 5 m/s^2 = 2800 kg.
The mass of an object can be determined by taking (the net force in Newtons) divided by (the acceleration in meters per second per second).
To find the mass of the truck in kilograms, divide the force in Newtons by the acceleration due to gravity (9.81 m/s^2). So, 50000 N ÷ 9.81 m/s^2 ≈ 5096 kg.