I think you mean the Schoenflies symmetry point group, and that can be determined by the geometry of XeOF4.
Based on the Lewis structure, the Oxygen is double bonded to Xe pointing up (z-direction), the Fluorine atoms are single bonded to Xe in a square formation along the x and y planes, and there is a lone pair of electrons pointing down (negative z-direction). This leads to AB5E1, or Square Pyramidal.
To determine the symmetry group, ask yourself the following questions where if the answer is no, move onto the next question:
1. Is this a molecule with low symmetry? (C1, Ci, Cs)
No.
2. Is this a molecule with high symmetry? (Td, Oh, CinfinityV, Dinfinityh, Ih)
No.
3. What is the highest-order rotation axis?
Looking down on the top of the molecule, (z-axis), you have a C4 rotation axis.
4. Is there a perpendicular C2 axis to the main rotation axis?
No.
[A no here lets you know that it is either a C or Sn group, whereas a yes leads to the D groups]
5. Is there a horizontal mirror plane?
No.
6. Is there a vertical mirror plane?
Yes, so the symmetry group is C4V
Hope this helps!
-Doc
XeO3 can be prepared by reacting xenon oxyfluoride (XeOF4) with water. XeOF4 can be prepared by the reaction of xenon with oxygen difluoride (OF2). Both reactions are carried out under controlled conditions in a laboratory setting.
The condensed molecular formula of methoxyethane(also known as ethyl methyl ether):methyl group -> -CH3methoxy group -> -OCH3ethyl group -> -CH2CH3Methoxy group + ethyl group = CH3- and -O- and -CH2CH3 the condensed molecular formula is: CH3OCH2CH3
A Molecular Substance or Compound.
You think probable to a glass.
The boiling points of alkenes depend on their molecular weight and structure. Generally, as the molecular weight of the alkene increases, so does its boiling point. Additionally, branching in the alkene structure tends to lower the boiling point compared to straight-chain alkenes of similar molecular weight.
Square bipyramidal.
XeO3 can be prepared by reacting xenon oxyfluoride (XeOF4) with water. XeOF4 can be prepared by the reaction of xenon with oxygen difluoride (OF2). Both reactions are carried out under controlled conditions in a laboratory setting.
The oxidation state of xenon (Xe) in XeOF4 is +6. This is because oxygen typically has an oxidation state of -2, so in XeOF4 with four oxygen atoms, the xenon must have an oxidation state of +6 to balance the charges.
The condensed molecular formula of methoxyethane(also known as ethyl methyl ether):methyl group -> -CH3methoxy group -> -OCH3ethyl group -> -CH2CH3Methoxy group + ethyl group = CH3- and -O- and -CH2CH3 the condensed molecular formula is: CH3OCH2CH3
The XeOF4 molecule is polar. This is because the molecule has a trigonal bipyramidal geometry with the lone pairs of electrons on the oxygen atom creating an uneven distribution of charge.
XeOF4 is prepared by reacting xenon hexafluoride with oxygen. On the other hand, XeO2F4 is not directly prepared from xenon as it is a hypothetical compound that has not been experimentally observed or synthesized.
A Molecular Substance or Compound.
The molecular formula of the methyl group is CH3. It consists of one carbon atom bonded to three hydrogen atoms.
No.
Hydoxyl
The molecular structure of cinnamaldehyde is a benzene ring with an aldehyde group (CHO) and an unsaturated carbon chain.
You think probable to a glass.