Quick serial number guide:No serial number, pre 1967 riflesSerial number range 400-419K 1967 rifleSerial number range 419-473K 1968 rifleSerial number range 2.1 million-2.59 million December 1968- January 1977 rifleSerial number range with an "A" prefix-post Feb 1977 rifle.
Not at all. First of all, 200 Celsius is not double 100 Celsius. To make this kind of comparisons, you have to use an absolute scale, i.e., Kelvin. 200 Celsius = 473K; 100 Celsius = 373K, so that is only about a 27% increase. Second, the energy emitted by a hot body is (roughly?) proportional to the 4th. power of the temperature. Raising the ratio to the fourth power gives you a factor of about 2.59 - the hotter body will radiate 2.59 times as much heat energy as the cooler body.
Using the ideal gas law, we can find the new volume by applying the formula: V2 = (V1 * T2) / T1 , where V1 = 5 liters, T1 = -50ยฐC + 273 = 223K, and T2 = 200ยฐC + 273 = 473K. Plugging these values into the formula gives V2 = (5 * 473) / 223 โ 10.6 liters.
Aniline can be converted to phenol through a diazotization reaction followed by a Sandmeyer reaction. First, aniline is treated with nitrous acid to form a diazonium salt. The diazonium salt is then reacted with water to replace the diazo group with a hydroxyl group, resulting in the formation of phenol.
The amount of heat energy (q) gained or lost by a substance is equal to the mass of the substance (m) multiplied by its specific heat capacity (Cg) multiplied by the change in temperature (final temperature - initial temperature) q = m x Cg x (Tf - Ti)q is what we are finding.m of coal = 5 kgCg of coal (anthracite) = 1.38 kJ/kg-K (kilojoules per kilogram-Kelvin)Tf = 220 °C.Ti = 20 °C.using the data above.q = m x Cg x (Tf - Ti)q = 5 x 1.38 x (220 - 20) -- temperature change same in K or °Cq = 5 x 1.38 x 200q = 1380 kilo-joules(kj) or 1.3 x 106 joules---The formula isQ=m*c*(T2-T1)Energy=mass*specific heat capacity*( temperature higher - temperature lower)(assuming the volume of your substance doesn't change during the heating)Energy Required = Mass x "Specific Heat Capacity" x Temperature changeFor anthracite coal, the specific heat is 1.38 kJ / kgK , yielding E = 1.38 (5kg)(200K) = 1380 kJ.
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