say for example the equilibrium I2(aq)+H2O(l)-----HOI(aq)+I(aq)+H(aq)
Think Lechatlier principle... addition of NaOH will cause the H ions to react with the OH ions to cause more water (more reactants) increase in reactants shifts the equilibrium in the FORWARD direction to form MORE H+ to restore the equilibrium
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The addition of NaOH increases the concentration of OH- ions in the solution, which will react with H+ ions to form water. This reaction decreases the concentration of H+ ions, leading to an increase in pH.
A base or alkaline substance lowers the H (hydrogen ion) concentration in a solution. Bases can accept or remove hydrogen ions from the solution, increasing the concentration of OH- ions and thereby reducing the concentration of H+ ions. Examples of bases include sodium hydroxide (NaOH) and ammonia (NH3).
The addition of sodium hydroxide (NaOH) increases the pH of a solution by releasing hydroxide ions (OH-) which combine with hydrogen ions (H+) to form water. However, the addition of sodium ions (Na+) alone does not directly impact the pH of a solution.
No, NaOH (sodium hydroxide) does not contain H+ ions. When NaOH dissolves in water, it dissociates into Na+ and OH- ions, with OH- being the hydroxide ions that can accept H+ ions to form water in a chemical reaction.
In a base, the concentration of hydrogen ions (H+) decreases as they accept protons to form hydroxide ions (OH-). This leads to an increase in the concentration of hydroxide ions, resulting in a higher pH and a more basic solution.
The balanced chemical equation for the reaction is H₂C₃H₂O₄ + 2NaOH → Na₂C₃H₂O₄ + 2H₂O. By stoichiometry, 1 mol of malonic acid reacts with 2 mol of NaOH. From the given data, the concentration of the malonic acid solution can be calculated to be 0.133 M.