Ethanol is C2H5OH and dimethyl ether is CH3-O-CH3. Both are C2H6O.
The product of the reaction of an alcohol C2H6O with itself is ethyl ether (C4H10O).
Balanced equation. C2H6O + 3O2 --> 2CO2 + 3H2O 0.274 moles C2H6O (2 moles CO2/1 mole C2H6O) = 0.548 moles carbon dioxide produced ============================
32 g ethanol is equivalent to 0,695 moles.
The chemical equation is:C2H5OH + O2 = 2 CO2 + 3 H2O
No! Looks like half a combustion reaction and I do not mean the half reaction method. C2H6O + 3O2 -> 2CO2 + 3H2O
C2H6O = 46.08 g 508 g * (1 mol C2H6O/46.08 g C2H6O) = 11.024 mol C2H6O There are about 11 moles in 508 grams of ethanol.
Ethanol is C2H5OH and dimethyl ether is CH3-O-CH3. Both are C2H6O.
The product of the reaction of an alcohol C2H6O with itself is ethyl ether (C4H10O).
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Balanced equation. C2H6O + 3O2 --> 2CO2 + 3H2O 0.274 moles C2H6O (2 moles CO2/1 mole C2H6O) = 0.548 moles carbon dioxide produced ============================
First figure the molar mass for each...C2H6O=46 & CH4O=32. Together C2H6O(46)+CH4O(32)= 78 Now you take molar mass / total molar mass So C2H6O(46)/total mass (C2H6O+CH4O)78= C2H60 or ethanol=0.410 and CH4O(32)/total mass 78=CH4O or methanol=0.589
C2H6O Like that.
This is the formula for Ethanol: C2H6O
C2H6O Can be CH3- CH2-OH Ethanol ( Ethyl alcohol) Can be CH3 - O - CH3 Dimethyl ether. The only two isomers.
Ethanol is C2H6O and it is an example of molecule.
C2H6O could be 1) Ethanol, CH3CH2OH 2) Dimethyl ether, CH3OCH3