Enough atoms to create bonding sites. Cellulose is an easy one. Its monomer is glucose. The formula for glucose is C6H12O6. To allow a glucose molecule to form part of a cellulosic structure, the tree has to "dehydrate" it by removing a hydrogen atom from one end and a hydroxide ion from the other end. You're left with C6H10O5, which then bonds with another like molecule and another and another.
Carbon and oxygen atoms in sugars are sourced from carbon dioxide (CO2) during the process of photosynthesis in plants. Plants absorb CO2 from the atmosphere and convert it into glucose through the Calvin cycle.
The enantiomer of D-glucose is L-glucose. It has the same molecular formula and structure as D-glucose but differs in the spatial arrangement of atoms, specifically at the chiral carbon (C5) where the hydroxyl group is oriented differently.
I believe that yes, it should occur - assuming any atoms are left. Please note that in the case of a neutron star, most of the atoms are crushed out of existence - i.e., there are no more atoms left, except a few in the outermost layers. Similarly, in a black hole, no atoms will be left.
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i think the glucose is the left over energy from when it had been germinating! :)
From left to right in a period the size of the atoms decreases.
Enough atoms to create bonding sites. Cellulose is an easy one. Its monomer is glucose. The formula for glucose is C6H12O6. To allow a glucose molecule to form part of a cellulosic structure, the tree has to "dehydrate" it by removing a hydrogen atom from one end and a hydroxide ion from the other end. You're left with C6H10O5, which then bonds with another like molecule and another and another.
Carbon and oxygen atoms in sugars are sourced from carbon dioxide (CO2) during the process of photosynthesis in plants. Plants absorb CO2 from the atmosphere and convert it into glucose through the Calvin cycle.
The enantiomer of D-glucose is L-glucose. It has the same molecular formula and structure as D-glucose but differs in the spatial arrangement of atoms, specifically at the chiral carbon (C5) where the hydroxyl group is oriented differently.
After 10740 years, half of the sample would have decayed, so there would be 200 atoms left. If the original sample had 400 atoms, then there would be 200 atoms left in the sample after 10740 years.
I believe that yes, it should occur - assuming any atoms are left. Please note that in the case of a neutron star, most of the atoms are crushed out of existence - i.e., there are no more atoms left, except a few in the outermost layers. Similarly, in a black hole, no atoms will be left.
The two molecules left after the complete breakdown of glucose during respiration are carbon dioxide (CO2) and water (H2O).
The equation is balanced because the number of each type of atom is the same on both sides of the equation. There are two Cl atoms on the left side and two Cl atoms on the right side, two Na atoms on the left side and two Na atoms on the right side, and two I atoms on the left side and two I atoms on the right side.
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In the reaction 2SO2 + O2 β 2SO3, there are 4 atoms of sulfur (S) present on the left side and 4 atoms of sulfur on the right side. There are 6 atoms of oxygen (O) on the left side and 6 atoms of oxygen on the right side.
when making a left turn, a person should turn on their left turn signal. They should look right, then left, and then make the turn.