carotene - 0.98
chlorophyll a - 0.59
chlorophyll b - 0.42
pheophytin - 0.81
xanthophyll 1 - 0.28
xanthophyll 2 - 0.15
everything is in percentages
To calculate the standard entropy change (ΔS°) for a reaction, you need to use the formula: [ \Delta S° = \sum S°{\text{products}} - \sum S°{\text{reactants}} ] You would sum the standard entropy values of the products and subtract the sum of the standard entropy values of the reactants. If you provide the specific reaction and the standard entropy values, I can calculate it for you.
To calculate the enthalpy of formation of Cl2NNF2(g), you can use the standard enthalpy of formation values of the reactants and products involved in the relevant chemical reaction. The enthalpy of formation is determined by the equation: ΔH_f° = ΣΔH_f°(products) - ΣΔH_f°(reactants). You need to find the standard enthalpy of formation for Cl2NNF2(g) and the standard enthalpies of the elements in their standard states (Cl2, N2, and F2) to perform this calculation. If the standard enthalpy values are not available, you may need to use Hess's law and related reactions to derive the value indirectly.
To figure out SATP (standard ambient temperature and pressure), you can refer to common values: 25 degrees Celsius (298.15 K) and 1 atm (101.3 kPa). These values are important for measuring gases at standard conditions.
This is a table with values in volts for the standard reduction potentials of metals to a cathode.
The three elements of a conflict are: incompatibility between goals or values, interaction between the parties involved, and perception of the disagreement by those involved.
Relationship between values goals and standard
carbon resistors of standard values are manufactured because other values can be obtained by series and parallel combination of standard values. Moreover even standard values do not offer exact Resistance's will have tolerance
It doesn't matter whether comparisons are involved. A small standard deviation indicates that population values are likely to be clustered closely around the mean.
The variance of a set of data values is the square of the standard deviation. If the standard deviation is 17, the variance can be calculated as (17^2), which equals 289. Therefore, the variance of the data values in the sample is 289.
11
When the two denominator values in the eclipse standard equation are the same, it can be said to be in foci.
List of values: -Strength -Flexibility -Weight -Price -etc
14 Apex
40
Answer
The Empirical Rule states that 68% of the data falls within 1 standard deviation from the mean. Since 1000 data values are given, take .68*1000 and you have 680 values are within 1 standard deviation from the mean.
Generally not without further reason. Extreme values are often called outliers. Eliminating unusually high values will lower the standard deviation. You may want to calculate standard deviations with and without the extreme values to identify their impact on calculations. See related link for additional discussion.