The chemical reaction is:
Pb(NO3)2 + Fe SO4 = PbSO4(s) + Fe(NO3)2
Fe(s) + 3AgNO3 ==> Fe(NO3)3 + 3Ag(s)
When barium nitrate and iron react, they undergo a single displacement reaction. The iron replaces the barium in the nitrate ion, forming iron(II) nitrate and barium as products. The chemical equation for this reaction is: Fe + Ba(NO3)2 -> Fe(NO3)2 + Ba.
Yes, zinc nitrate can react with iron in a chemical reaction known as a displacement reaction. In this reaction, the more reactive zinc displaces the less reactive iron from its compound, forming zinc nitrate and iron nitrate as products. The reaction can be represented by the equation: Zn(NO3)2 + Fe → Fe(NO3)2 + Zn.
Iron (II) sulfate is the correct name for this compound. The Fe ion has a charge of 2 and so does the sulfate ion, so there is no subscript after them.
Fe(SO4)3 is Iron(III) sulfate Wrong: Fe2(SO4)3 is iron(III) sulfate.
Yes Fe+Pb(NO3)2--->Pb+Fe(NO3)2 Blarin i merked u
2Fe(NO3)3 + 3Na2SO4 -> Fe2(SO4)3 + 6NaNO3
The iron will replace the copper in the copper(II) nitrate solution, forming iron(II) nitrate and copper metal as products. The balanced chemical equation for the reaction is: Fe + Cu(NO3)2 -> Fe(NO3)2 + Cu.
Sodium Nitrate is NaNO3 Iron sulfate (I am assuming that you are referring to iron (ii)) is FeSO4 2 NaNO3 + 1 FeSO4 --> 1 Na2SO4 + 1 Fe(NO3)2 This is a double replacement reaction, and it occurs because Fe(NO3)2 is a precipitate.
Fe(s) + 3AgNO3 ==> Fe(NO3)3 + 3Ag(s)
The reaction is:Fe + PbSO4 = Pb + FeSO4
anhydrous iron(III) nitrate (ferric nitrate) is Fe(NO3)3 there is a hydrate Fe(NO3)9H2O Iron(II) nitrate (ferrous nitrate) is Fe(NO3)2.
When barium nitrate and iron react, they undergo a single displacement reaction. The iron replaces the barium in the nitrate ion, forming iron(II) nitrate and barium as products. The chemical equation for this reaction is: Fe + Ba(NO3)2 -> Fe(NO3)2 + Ba.
lead(II) nitrate is Pb(NO3)2; lead(IV) nitrate is Pb(NO3)4.
The reaction between iron and copper nitrate in a single replacement reaction would produce iron(II) nitrate and copper metal. The iron would replace the copper in the nitrate compound, resulting in the formation of iron(II) nitrate and copper metal as products.
The word equation would be iron reacts with lead nitrate to form iron two nitrate and lead.Or perhaps you meant this?The word equation would be Iron + Lead Nitrate => Iron (II) Nitrate + LeadThe chemical equation would be Fe(s) + Pb(NO3)2 => Fe(NO3)2 + PbI assume you are having problems with the charge the iron nitrate would go into, so here is a link that helps describe how to determine the charges of the ions of transitional metals: http://indiescience.org/basetalk/index.php?topic=13.0
The balanced equation for zinc nitrate (Zn(NO3)2) and ferrous sulfate (FeSO4) is: Zn(NO3)2 + FeSO4 -> ZnSO4 + Fe(NO3)2.