The volume of a cylinder is calculated using the formula V = πr^2h, where r is the radius and h is the height. The radius of a cylinder with a diameter of 6' is 3'. Thus, the volume of the cylinder is approximately 3390 cubic feet. There are about 7.48 gallons in a cubic foot, so the total volume is equivalent to about 25,379 gallons of water.
R=RoA1/3 where Ro = 1.2 fm and A= mass no.So R= 1.2 (216)1/3 = 1.2 X 6 = 7.2 femtometers or 7.2 X 10-15 m
CFCs, and are known ozone depleters. See the link below for what their effects are.: * Refrigerant R-10 is CCl4. * Refrigerant R-11 is CCl3F. * Refrigerant R-12 is CCl2F2. * Refrigerant R-13 is CClF3. HCFCs, and are known ozone depleters but with lowered suvivability to reach the ozone layer. See the link below for what its effects are. * Refrigerant R-22 is HCClF2. * Refrigerant R-40 is CH3Cl. It is responsible for ~17% of chlorine-assisted ozone destruction in the statosphere. It is today primarily produced by plants, and the combustion of organic waste materials, since its use in industry was stopped some time ago. CFCs inclusive of HCFCs, are ~82% of the chlorine currently found in the stratosphere Some refrigerants that do not contain chlorine or bromine are: R-14, R-23, R-32, R-41, R-50, R-116, R-125, R-E125, R-134, R-134a, R-E134, R-143, R-143a, R-143m, R-E143a, R-152, R-152a, R-161, R-170, R-218, R-227ca, R-227ca2, R-227ea, R-227me, R-236cb, R-236ea, R-236fa, R-236me, R-FE-36, R-245ca, R-245cb, R-245ea, R-245eb, R-245fa, R-245mc, R-245mf, R-245qc, R-254cb, R-254pc, R-263, R-272, R-281, R-290, R-C318, R-3-1-10, R-347mcc, R-347mmy, R-365mfc, a few of the blends between R-400 and R-600, R-600, R-600a, R-601, R-601a, R-610, R-611, R-630, R-631, R-702, R-704, R-717, R-718, R-720, R-728, R-732, R-740, R-744, R-744A, R-764, R-784, R-1114, R-1132, R-1141, R-1150, R-1216, R-1270 This list includes chemicals that are so stable that they also can accumulate over decades as CFCs did, and yet new problems may result from their use and/or release into the environment. Others of them are fuels (so are flammable), components of natural gas, and may not accumulate, but can contribute to ozone pollution as a VOC.
This is R-502 with a boiling point at -45 0C.
R-choh-ch3 +h2so4 -> R-ch=ch2 R-ch=ch2 + HBr -> R-ch2-ch2Br R-ch2-ch2Br + H2O -> R-ch2-ch2oh + HBr
d = r + 6 now you make the equation relating what happened 6 yrs ago, remembering that then they were r-6 and d-6: dr = 2(r-6)(d-6) plug the first eqn into the second one and solve: r(r+6) = 2(r-6)(r) you can cancel an r, since r isn't 0! r+6 = 2(r-6) r=18 So Ricardo is 18 and his sis is 24.
If r=9, then r*6 would be 9*6, or 54.
6
r9 - 6 = 12 then r is 2
r=square root sign. r(6)*r(10)=r(6*10)=r(60)=2r(15)
1 to 6 = 2 to 12
a+r-1
Circumference is equal to 2(pi)r. So if C = 6, and 2(3.14)r = C, then solve for r r= 6/2(3.14) = .955
I think so.r2 + 7r + 6 = [ (r+6) (r+1) ]
LouisBest Answer louis was prank calling 118 and they asked him for an adress and he was spelling terrence Lou: T E R R R R R R 118: how many R's are there? Lou: Err, 6!
45/r
That depends on what the question is. What you gave is simply a relationship between two variables. You can simplify it like this: 4x + 8 = 2r + 20 (4x + 8) / 2 = (2r + 20) / 2 2x + 4 = r + 10 2x + 4 - 4 = r + 10 - 4 2x = r + 6 You can then solve for x by dividing both sides by two: 2x / 2 = (r + 6) / 2 x = r/2 + 3 You could also solve for r by subtracting six from both sides, and rearranging the equation: 2x = r + 6 2x - 6 = r + 6 - 6 2x - 6 = r r = 2x - 6 r = 2(x - 3)