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This equation is an example of what nuclear decay 232 90 Th to 4 2 He plus 228 88 Ra?
Alpha
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How would you write a nuclear equation for the most likely mode of decay for the unstable nuclide Kr-74?
Krypton-74 will most likely undergo beta decay, and the type of beta decay an observer will encounter will be beta plus decay. A proton in the nucleus will undergo a change and become a neutron, and a positron (e+) and an antineutrino (ve) will emerge from the reaction. The krypton-74 atom will transmute into a bromine-74 atom. The equation will look something like this: 3674Kr => 3574Br + e+ + ve
What is the equation for the beta decay of barium-140?
The beta decay of barium-140 involves a neutron turning into a proton, releasing an electron (beta particle) and an antineutrino. The equation for this decay is: 56^140Ba -> 57^140La + e^- + v̄_e
The following equation is an example of decay 185 79 Au -- 4 2 He plus 181 77 Ir?
alpha
How do you write a balanced nuclear equation for the positron emission of nitrogen-13?
If oxygen-16 was to undergo positron emission (beta plus decay), a proton in its nucleus would transform into a neutron (mediated by the weak force). The oxygen-16 would become nitrogen-16, and we'd see a positron and a neutrino appear. The equation might look like this: 816O => 716N + e+ + ve It is easy to write a balanced nuclear equation for any nuclide undergoing positron emission. Note the subscript numerals at the beginning of each element. That's the atomic number of that element. The superscript numerals are the atomic mass of the nuclide. When beta plus decay occurs, nuclear transformation takes place. The atomic number of the element goes down by one, and one element becomes another element. The subscripted numerals will reflect that decrease of one, and the atomic mass (the superscripted numerals) will remain the same. Note the last two factors in the equation, as they are the positron and the neutrino, respectively. That's the long and short of the beta plus decay of O-16, as asked. We'll add, however, that oxygen-16 is a stable isotope of oxygen. It does not undergo beta decay, but for the sake of argument, it did here. And with the results shown. By the way, it is oxygen-15 that is the radioactive isotope of oxygen that will undergo beta plus decay. You'll find links below for more information.
What nuclear reaction is beta decay?
Beta decay is a type of radioactive decay. It comes in two "flavors" or types, and they are beta plus decay and beta minus decay. The weak interaction (or weak force, or weak nuclear force) mediates this type of decay, and it allows for a change in the nucleus of an atom. Let's look at the two types. In beta minus decay, a neutron in an atom's nucleus will be converted into a proton. This happens when one of the down quarks which make up the neutron is converted into an up quark. As the change occurs, an electron will be ejected from the nucleus along with an antineutrino. The transmutation of an atom, an element, will have taken place. The new atom will have an atomic number 1 greater than that of the original element. This is nuclear transmutation. If you're interested in the equation, it looks like this: n -> p + e- + -ve In that equation, the symbols are for the neutron, proton, electron and antineutrino, respectively. In a beta plus decay event, a proton in an atom's nucleus will be converted into a neutron. One of the up quarks in the proton will be converted into a down quark. When this change occurs, a positron will be ejected from the nucleus, along with a neutrino. An atom so affected will have its atomic number go down by 1 and it, too, will have undergone transmutation to a new element. The equation for this reaction looks like this: p -> n + e+ +ve In this equation, the symbols are for the proton, neutron, positron and neutrino, respectively. Use the links below for more information on beta decay and what happens when it occurs.
What kind of nuclear reaction is seen in 9039Y 9040Zr plus 0-1e?
This is an example of beta decay, specifically beta-minus decay. In this reaction, a neutron in the nucleus is transformed into a proton, electron, and anti-neutrino. This results in the formation of 90Zr from 90Y.
How would you write a nuclear equation for the most likely mode of decay for the unstable nuclide Kr-74?
Krypton-74 will most likely undergo beta decay, and the type of beta decay an observer will encounter will be beta plus decay. A proton in the nucleus will undergo a change and become a neutron, and a positron (e+) and an antineutrino (ve) will emerge from the reaction. The krypton-74 atom will transmute into a bromine-74 atom. The equation will look something like this: 3674Kr => 3574Br + e+ + ve
Is 3a 12 plus a 6 a Equation?
Yes. 3a plus 12 plus 6 is an example of an Equation.
When sodium is conrted into a neutron in a beta plus decay?
When sodium is converted into an neutron it will result in the nuclear transmutation.
What kind of nuclear reaction is seen in 146 62 Sm 142 60 Nd plus 4 2 He?
Alpha decay
Write a balanced nuclear equation for the radioactive decay of a boron-10 plus a neutron results in the formation of another element and the release of an alpha particle?
Boron-10 (^10B) undergoing neutron capture forms boron-11 (^11B), followed by the emission of an alpha particle (helium-4 atom). The balanced nuclear equation would be: ^10B + n → ^11B + ^4He
4n plus 2 equals 25 is and example of?
An equation
What is the equation for the beta decay of barium-140?
The beta decay of barium-140 involves a neutron turning into a proton, releasing an electron (beta particle) and an antineutrino. The equation for this decay is: 56^140Ba -> 57^140La + e^- + v̄_e
4n plus 2 equals 25 is an example of what property?
Equation
What is missing in the following nuclear equation 99 43 tc plus 99 44 ru?
beta particle
What is missing in the following nuclear equation 247 95Am plus 247 96 Cm?
Beta -apex- :D
Thorium -234 proatinium-234 plus -1?
Thorium-234 does not decay into Protactinium-234. Instead, Thorium-234 naturally decays by alpha emission to Protactinium-230. The difference in decay modes is due to variances in their nuclear structures and energetics.
